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lukranit [14]
3 years ago
10

Doubling the voltage in a circuit doubles the current if what is held constant?

Physics
1 answer:
antiseptic1488 [7]3 years ago
4 0
The Resistance needs to be the same to allow the current to double with the voltage.
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Un tubo cilindrico hueco de cobre mide 3 m de longitud tienen un diametro exterior de 4cm y un diametro interior de 2 cm¿cuanto
Irina-Kira [14]

Answer:

 W = 9.93 10² N

Explanation:

To solve this exercise we must use the concept of density

           ρ = m / V

the tabulated density of copper is rho = 8966 kg / m³

let's find the volume of the cylindrical tube

           V = A L

           V = π (R_ext  ² - R_int ²) L

let's calculate

          V = π (4² - 2²) 10⁻⁴  3

          V = 1.13 10⁻²  m³

         m = ρ V

        m = 8966 1.13 10⁻²

        m = 1.01 10² kg

the weight of the tube

        W = mg

         W = 1.01 10² 9.8

         W = 9.93 10² N

4 0
2 years ago
Which two statements describe how ultrasound technology produces an image of a baby before it is born?
Elan Coil [88]

Answer:a and c

Explanation:

8 0
3 years ago
Read 2 more answers
An elevator car weighs 5500 N. If the car accelerates upwards at a rate of 4.0 m/s2, what is the tension in the support cable li
nadya68 [22]

Answer:

Explanation:

The equation for this, since we are talking about weight on an elevator, is Newton's 2nd Law adjusted to fit our needs:

F_n=ma+w where the Normal Force needed to lift that elevator car is the tension. So the equation then becomes

T = ma + w where T is the tension in the cable to lift the elevator, m is the mass of the elevator (which we have to solve for), a is the acceleration of the elevator (positive since it's going up), and w is the weight of the elevator (which we have as 5500 N). Solving first for mass:

w = mg and

5500 =- m(10) so

m = 550 kg. Now we have what we need to solve for the tension:

T = 550(4.0) + 5500 and

T = 2200 + 5500 so

T = 7700 N

4 0
3 years ago
What is the sum of 231 + 5080 + 80 + 13 + 9​
Gemiola [76]

Answer:

5413

Explanation:

add them up

6 0
3 years ago
10. A book has a mass of 400 g. The surface of the book in contact with a table has dimensions 0.10m x 0.20 m. The gravitational
morpeh [17]

The pressure exerted on the table due to the book is 200 N/m².

The given parameters;

  • <em>mass of the book, m = 400 g = 0.4 kg</em>
  • <em>dimension of the table,  = 0.10m x 0.20 m.</em>
  • <em>gravitational field strength g =  10 N/kg.</em>

The area of the table is calculated as follows;

A = 0.1 x 0.2 = 0.02 m²

The pressure exerted on the table due to the book is calculated as follows;

P = \frac{F}{A}

where;

  • <em>F is the force of the book due to its weight</em>

<em />

P =\frac{F}{A} = \frac{mg}{A} = \frac{0.4 \times 10}{0.02} = 200 \ N/m^2

Thus, the pressure exerted on the table due to the book is 200 N/m².

Learn more here:brainly.com/question/21935783

8 0
2 years ago
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