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4 years ago

Doubling the voltage in a circuit doubles the current if what is held constant?

Physics

1 answer:

antiseptic1488 [7]4 years ago

4 0

The Resistance needs to be the same to allow the current to double with the voltage.

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While John is traveling along a straight interstate highway, he notices that the mile marker reads 239 km. John travels until he

Doss [256]

Answer:

72 km

Explanation:

We are given that

John marker reads=239 km

John travels and reaches the marker=149 km

John retraces his path and reaches the marker=167 km

We have to find the John's resultant displacement from 239 km.

Displacement:The displacement is the distance between two positions.

By definition of displacement

John's resultant displacement from 239 km=239-167

John's resultant displacement from 239 km=72 km

Hence, John's resultant displacement from 239 km=72 km

4 0

4 years ago

HELP! DUE TOMORROW!! specify the independent and dependent variables, as well as constants. 4-6! only!

olga55 [171]

Answer:

the variables in a study of a cause-and-effect relationship are called the independent and dependent variables. The independent variables is the cause and the dependent variables is the effects. It's value depends on the changes in the independent variable.

Explanation:

I hope this small infor is helpful

5 0

3 years ago

All points to the of zero on a horizontal number line are negative

Mumz [18]

Numbers on the left of zero are negative. Number lines go from smallest to greatest.

5 0

3 years ago

Read 2 more answers

A .5 kg air puck moves to the right at 3 m/s, colliding with a 1.5kg air puck that is moving to the left at 1.5 m/s.

arlik [135]

Answer:

part (a) v = 1.7 m/s towards right direction

part (b) Not an elastic collision

part (c) F = -228.6 N towards left.

Explanation:

Given,

Mass of the first puck = $m_1\ =\ 5\ kg$
Mass of the second puck = $m_2\ =\ 3\ kg$
initial velocity of the first puck = $u_1\ =\ 3\ m/s.$
Initial velocity of the second puck = $u_2\ =\ -1.5\ m/s.$

Part (a)

Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.

From the conservation of linear momentum,

$m_1u_1\ +\ m_2u_2\ =\ (m_1\ +\ m_2)v\\\Rightarrow v\ =\ \dfrac{m_1u_1\ +\ m_2u_2}{m_1\ +\ m_2}\\\Rightarrow v\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5}{5\ +\ 1.5}\\\Rightarrow v\ =\ 1.7\ m/s.$

Direction of the velocity is towards right due to positive velocity.

part (b)

Given,

Final velocity of the second puck = $v_2\ =\ 2.31\ m/s.$

Let $v_1$ be the final velocity of first puck after the collision.

From the conservation of linear momentum,

$m_1u_1\ +\ m_2u_2\ +\ m_1v_1\ +\ m_2v_2\\\Rightarrow v_1\ =\ \dfrac{m_1u_1\ +\ m_2u_2\ -\ m_2v_2}{m_1}\\\Rightarrow v_1\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5\ -\ 1.5\times 2.31}{5}\\\Rightarrow v_1\ =\ 1.857\ m/s.$

For elastic collision, the coefficient of restitution should be 1.

From the equation of the restitution,

$v_1\ -\ v_2\ =\ e(u_2\ -\ u_1)\\\Rightarrow e\ =\ \dfrac{v_1\ -\ v_2}{u_2\ -\ u_1}\\\Rightarrow e\ =\ \dfrac{1.857\ -\ 2.31}{-1.5\ -\ 3}\\\Rightarrow e\ =\ 0.1\\$

Therefore the collision is not elastic collision.

part (c)

Given,

Time of impact = t = $25\times 10^{-3}\ sec$

we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,

$\therefore I\ =\ \ m_1v_1\ -\ m_1u_1\\\Rightarrow F\times t\ =\ m_1(v_1\ -\ u_1)\\\Rightarrow F\ =\ \dfrac{m_1(v_1\ -\ u_1)}{t}\\\Rightarrow F\ =\ \dfrac{5\times (1.857\ -\ 3)}{25\times 10^{-3}}\\\Rightarrow F\ =\ -228.6\ N$

Negative sign indicates that the force is towards in the left side of the movement of the first puck.

3 0

3 years ago

Which of the following is an ecosystem

iogann1982 [59]

A it is Green plants.

or they all

7 0

3 years ago