All categories

3 years ago

PLEASE ANSWER ASAP

Physics

1 answer:

Mekhanik [1.2K]3 years ago

8 0

Answer:

yes h h jj h v gu i kj

Explanation:

jjejejejejj

You might be interested in

At the point of fission, a nucleus of ^235 U that has 92 protons is divided into two smaller spheres, each of which has 46 proto

IrinaK [193]

Answer : $F = 3.5\times10^{3}\ N$

Explanation :

Given that

Radius of sphere $r = 5.90\times 10^{-15}\ m$

The distance between the centers of the two spheres is

$r = 2\times 5.90\times 10^{-15}\ m$

The charge of the sphere $q = 46\times1.6\times10^{-19} C$

The magnitude of the repulsive force between the charges pushing them a part is

Using coulomb law

$F = \dfrac {kq_{1}q_{2}}{r^{2}}$

$F = \dfrac{9\times10^{9}\times (46\times1.6\times10^{-19})^{2}C^{2}}{2\times(5.90\times10^{-15})^{2}\ m^{2}}$

$F = 3501.3\ N$

$F = 3.5\times10^{3}\ N$

Hence, this is the required solution.

3 0

3 years ago

A 12,500 N alien UFO is hovering about the surface of Earth. At time , its position can be given as () = ((0.24 m/s^3)^3 + 25 m)

stepladder [879]

a) $F=(3675i-4543k)N$

b) 5843 N

Explanation:

The position of the UFO at time t is given by the vector:

$r(t)=(0.24t^3+25)i+(4.2t)j+(-0.43t^3+0.8t^2)k$

Therefore it has 3 components:

$r_x=0.24t^3+25\\r_y=4.2t\\r_z=-0.43t^3+0.8t^2$

We start by finding the velocity of the UFO, which is given by the derivative of the position:

$v_x=r'_x=\frac{d}{dt}(0.24t^3+25)=3\cdot 0.24t^2=0.72t^2\\v_y=r'_y=\frac{d}{dt}(4.2t)=4.2\\v_x=r'_z=\frac{d}{dt}(-0.43t^3+0.8t^2)=-1.29t^2+1.6t$

And then, by differentiating again, we find the acceleration:

$a_x=v'_x=\frac{d}{dt}(0.72t^2)=1.44t\\a_y=v'_y=\frac{d}{dt}(4.2)=0\\a_z=v'_z=\frac{d}{dt}(-1.29t^2+1.6t)=-2.58t+1.6$

The weight of the UFO is W = 12,500 N, so its mass is:

$m=\frac{W}{g}=\frac{12500}{9.8}=1276 kg$

Therefore, the components of the force on the UFO are given by Newton's second law:

$F=ma$

So, Substituting t = 2 s, we find:

$F_x=ma_x=(1276)(1.44t)=(1276)(1.44)(2)=3675 N\\F_y=ma_y=0\\F_z=ma_z=(1276)(-2.58t+1.6)=(1276)(-2.58(2)+1.6)=-4543 N$

So the net force on the UFO at t = 2 s is

$F=(3675i-4543k)N$

The magnitude of a 3-dimensional vector is given by

$|v|=\sqrt{v_x^2+v_y^2+v_z^2}$

where

$v_x,v_y,v_z$ are the three components of the vector

In this problem, the three components of the net force are:

$F_x=3675 N\\F_y=0\\F_z=-4543 N$

Therefore, substituting into the equation, we find the magnitude of the net force:

$|F|=\sqrt{3675^2+0^2+(-4543)^2}=5843 N$

7 0

3 years ago

When light passes through sequential interfaces, there may be a change of phase upon reflection at each interface.

Lena [83]

That's true.

I have a hunch that there definitely IS a change of phase at every reflection.

4 0

2 years ago

Help i forgot to complete this worksheet

Naily [24]

just search up the answer/ definition to all of them, rephrase into own words, then do the same for examples.

6 0

3 years ago

How would doubling the mass of Earth affect the gravity we experience?

N76 [4]

The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases.

5 0

3 years ago