<span>When still rolling your bike had kinetic energy, or energy in the form of motion. The forces resisting this motion--a mixture of many factors including air resistance, tire friction, friction in the hubs of the wheels, etc...--eventually decrease the kinetic energy of the bike to zero as it reaches a complete stop.</span>
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Hi there!
To find the final velocity of an object dropped from rest, we can used the simplified equation:
vf = √2gh
Plug in the given values: (g = 9.8 m/s²)
vf = √2(9.8)(100) ≈ 44.272 m/s
Answer:
The minimum difference between the lengths of the two tubes should be 0.385 meters.
Explanation:
As we known that for any two waves to arrive in phase at any point the difference in the path traveled by the waves should be an integral multiple of the wavelength of the wave.
Mathematically we can write:
For the given wave we have
Applying values we get
Thus the minimum difference in the lengths of the tubes can be obtained by putting the value of n = 1
Answer:
Explanation:
λ=c x²
c = λ / x²
λ is mass / length
so its dimensional formula is ML⁻¹
x is length so its dimensional formula is L
c = λ / x²
= ML⁻¹ / L²
= ML⁻³
B )
We shall find out the mass of the rod with the help of given expression of mass per unit length and equate it with given mass that is M
The mass in the rod is symmetrically distributed on both side of middle point.
we consider a small strip of rod of length dx at x distance away from middle point
its mass dm = λdx = cx² dx
By integrating it from -L to +L we can calculate mass of whole rod , that is
M = ∫cx² dx
= [c x³ / 3] from -L/2 to +L/2
= c/3 [ L³/8 + L³/8]
M = c L³/12
c = 12 M L⁻³
C ) Moment of inertia of rod
∫dmx²
= ∫λdxx²
= ∫cx²dxx²
= ∫cx⁴dx
= c x⁵ / 5 from - L/2 to L/2
= c / 5 ( L⁵/ 32 +L⁵/ 32)
= (2c / 160)L⁵
= (c / 80) L⁵
= (12 M L⁻³/80)L⁵
= 3/20 ML²
=
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