Voltage =Current * Resistance
= 9 * 43
Voltage = 387 V
The potential difference does work on the electron. The work is given by:
W = Vq
W = work, V = potential difference, q = electron charge
Given values:
V = 6V, q = 1.6x10^-19C
Plug in and solve for W:
W = 6(1.6x10^-19)
W = 0.96aJ
Formula for Electric Field strength , E = V/d
where V = Voltage in volts, and d = distance of separation in meters.
d = 0.5 cm = 0.005 m, V = 12 V
E = V/d = 12 / 0.005
E = 2400
Electric Field Strength = 2400 Volts/meter
Answer:
1) Position time graph
2) Acceleration time graph
3) Velocity time graph