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Anastaziya [24]
3 years ago
7

How do you find the atoms of nitrogen in this substance (NH4)2CO3?

Chemistry
1 answer:
Katen [24]3 years ago
3 0
6.022*10^23 is the answer
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How many grams of octane (C8H18) must be burned to produce 300.0g of CO2?
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Answer:

m_{C_8H_{18}}=85.67gC_8H_{18}

Explanation:

Hello there!

In this case, according to the given combustion reaction of octane, it is possible for us to perform the stoichiometric method in order to calculate the mass of octane that is required to consume 300.0 g of oxygen by considering the 2:25 mole ratio, and the molar masses of 114.22 g/mol and 32.00 g/mol respectively:

m_{C_8H_{18}}=300.0gO_2*\frac{1molO_2}{32.00gO_2}*\frac{2molC_8H_{18}}{25molO_2}*\frac{114.22gC_8H_{18}}{1molC_8H_{18}}   \\\\m_{C_8H_{18}}=85.67gC_8H_{18}

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