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3 years ago

So in general what rule can you make about substances that dissolve in solvent?

2 answers:

4 0

Can I ask you something? Are you talking about polar and non polar solvents? If so, then it's quite simple. Polar solutes dissolve in polar solvents and non polar solutes dissolve on non polar solvent. Hope it's helpful. If not, let me know.

spin [16.1K]3 years ago

3 0

In general, SOLUBILITY is an ability of a substance to dissolve. In the process of dissolving, the substance which is being dissolved is called a solute and the substance in which the solute is dissolved is called a solvent. A mixture of solute and solvent is called a solution.

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What volume will 3.0 moles of O2 gas occupy at S.T.P?

REY [17]

Answer:

3 moles of oxygen at STP will occupy a volume of 3×22. 4=67. 2 L.

Explanation:

6 0

1 year ago

Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 4.90 moles of magnesium perchlorate, Mg(ClO4)2.]\

Leviafan [203]

Answer:

4.90 moles of $Mg(ClO_4)_2$ will produce (9.8) moles of $Cl^{-}$ ,

(4.90) moles of $Mg^{2+}$ and

(39.2) moles of $O^{2-}$

Explanation:

From the question we are told that

The number of moles of is $n = 4.90 \ mols$

The formation reaction of $Mg(ClO_4)_2$ is

$Mg^{2+} + 2 Cl^{-} + 8O^{2+} \to Mg(ClO_4)_2$

From the reaction we see that

1 mole of $Mg(ClO_4)_2$ is formed by 2 moles of $Cl^{-}$ 1 mole of $Mg^{2+}$ and 4 $O^{2-}$

This implies that

4.90 moles of $Mg(ClO_4)_2$ will produce (2 * 4.90) moles of $Cl^{-}$ ,

(1 * 4.90) moles of $Mg^{2+}$ and

(8 * 4.90) moles of $O^{2-}$

4.90 moles of $Mg(ClO_4)_2$ will produce (9.8) moles of $Cl^{-}$ ,

(4.90) moles of $Mg^{2+}$ and

(39.2) moles of $O^{2-}$

4 0

3 years ago

Read 2 more answers

During the following chemical reaction, 46.3 grams of C3H6O react with 73.2 grams of O2

ra1l [238]

Answer:

a) O2 is the limiting reactant

b) 75.70 grams CO2 (theoretical yield)

c) There remains 12.81 grams of C3H6O

d) The actual yield CO2 is 34.29 grams

Explanation:

Step 1: Data given

Mass of C3H6O = 46.3 grams

Mass of O2 = 73.2 grams

Molar mass of C3H6O = 58.08 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

C3H6O + 4O2 → 3 CO2 + 3H2O

Step 3: Calculate moles C3H6O

Moles C3H6O = mass C3H6O / molar mass C3H6O

Moles C3H6O = 46.3 grams / 58.08 g/mol

Moles C3H6O = 0.793 moles

Step 4: Calculate moles O2

Moles O2 = 73.2 grams / 32 g/mol

Moles O2 = 2.29 moles

Step 5: Calculate limiting reactant

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed. (2.29 moles).

C3H6O is in excess. There will react 2.29/4 = 0.5725 moles C3H6O

There will remain 0.793 - 0.5725 = 0.2205 moles C3H6O

This is 0.2205 moles * 58.08 g/mol = 12.81 grams

Step 6: Calculate moles of CO2

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

For 2.29 moles O2 we need 3/4 * 2.29 = 1.72 moles CO2

This is 1,72 moles * 44.01 g/mol = 75.70 grams CO2

Step 7: Calculate actual yield

% yield = 45.3 % = 0.453 = (actual yield / theoretical yield)

actual yield = 0.453 * 75.70 = 34.29 grams

3 0

3 years ago

To practice for an Ironman competition, John rode his bike for 15 kilometers. How many

puteri [66]

Answer:

15000

Explanation:

1000 Meters in a kilo meter. So multiply 15 by a 1000.

6 0

3 years ago

How can scientists know what happened millions of years ago if no one was there to see it?

xxMikexx [17]

Answer:

In the 150 years since Darwin proposed the theory of evolution by natural selection, a mountain of evidence has accumulated ... How can you know what happened millions of years ago if no one was there to see it? Evidence and observation are the building blocks of all scientific inquiry; evolutionary science is no different

Explanation:

4 0

3 years ago