The Length of FD = 26 cm
According to the given information
FE = FC = 12cm
As FE, FC both are radius of circle
The tangent segments to a circle from a external point are equal
Hence
CD = ED
13x - 16 = 4x + 11
13x - 4x = 11 + 16
9x = 27
x = 27/9
x = 3
CD = 13x - 16
= 13 × 3 - 16
= 23 cm
ED = 4x + 11
= 4 × 3 + 11
= 23 cm
In Triangle FED
FE is perpendicular to ED
According to Pythagoras Theorem
=
= 673
FD = 26 cm approx.
The Length of FD = 26 cm
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Answer:
The answer is;
54.4
Step-by-step explanation:
The given parameter are;
Triangle ΔFGH = Right triangle
The length of segment = 48
The measure of ∠HFG = 28°
The measurement required = The measure of segment = x
The measure of ∠FHG = 90° angle opposite hypotenuse side of a right triangle
Therefore, ∠FGH = 180° - ∠HFG - ∠FHG = 180° - 90° - 28° = 62°
∠FGH = 62°
By sine rule, we have;
/(sin ∠FGH) =
/(sin(∠FHG)
By substituting the known values, we have;
48/(sin 62°) = x/(sin(90°)
sin(90°) = 1, therefore, we have;
x/1 = x = 48/(sin 62°) = 54.4 (by rounding the answer to the nearest tenth)
x = 54.4