Answer:
Width = 2x²
Length = 7x² + 3
Step-by-step explanation:
∵ The area of a rectangle is 
∵ Its width is the greatest common monomial factor of
and 6x²
- Let us find the greatest common factor of 14 , 6 and
, x²
∵ The factors of 14 are 1, 2, 7, 14
∵ The factors of 6 are 1, 2, 3, 6
∵ The common factors of 14 and 6 are 1, 2
∵ The greatest one is 2
∴ The greatest common factor of 14 and 6 is 2
- The greatest common factor of monomials is the variable with
the smallest power
∴ The greatest common factor of
and x² is x²
∴ The greatest common monomial factor of
and 6x² is 2x²
∴ The width of the rectangle is 2x²
To find the length divide the area by the width
∵ The area = 
∵ The width = 2x²
∴ The length = (
) ÷ (2x²)
∵
÷ 2x² = 7x²
∵ 6x² ÷ 2x² = 3
∴ (
) ÷ (2x²) = 7x² + 3
∴ The length of the rectangle is 7x² + 3
Answer:
C: 1.5
Step-by-step explanation:
For point D, the y value goes from 4 -> 6. This means that 4x = 6 ,
.
For point F, both values (x and y) are multiplied by 1.5.
The area is 84.
What I do it cut the polygon into something easier like a square and rectangle.
Rectangle: 6•12=72
Square: 4•3=12
Add them together and you have 84
Answer:
...so cos t = cot t can only happen when cos t is 0 or sin t is 1. (But sin t = 1 only happens when cos t = 0, so cos t = 0 is enough.)
arccos(0) is pi/2, plus or minus any multiple of pi.
Step-by-step explanation:
cotθ = cosθ
cosθ/sinθ = cosθ
sinθ = 1
θ = π/2
pi also = to 3.14 etc.