The direct sunlight at Earth's surface is about 1050 W/m2 . Compute mass lost by Sun in a thousand years as a fraction of Earth
1 answer:
Answer:
Explanation:
Energy falling on 1 m² surface of earth per second = 1050
Energy in one million years on 1 m²
= 1050 x 60 x 60 x 24 x 365 x 10⁶ = 3.311 x 10¹⁶ J
In order to calculate total energy coming out of the surface of the sun , we shall have to sum up this energy for the while spherical surface of imaginary sphere having radius equal to distance between sun and earth.
Area of this surface = 4π R² = 4 X 3.14 X (149.6 X 10⁹ )²
= 2.8 X 10²³ m²
So total energy coming out of the sun = 2.8 x 10²³ x 3.311 x 10¹⁶
= 9.271 x 10³⁹ J
From the formula
E = mc² { energy mass equivalence formula }
m = E / c² =
1.03 x 10²³ kg
mass of earth = 5.972 x 10²⁴
Answer in percentage of mass of earth
=
= 1.72 %
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Answer:
I(x) = 1444×k ×
I(y) = 1444×k ×
I(o) = 3888×k ×
Explanation:
Given data
function = x^2 + y^2 ≤ 36
function = x^2 + y^2 ≤ 6^2
to find out
the moments of inertia Ix, Iy, Io
solution
first we consider the polar coordinate (a,θ)
and polar is directly proportional to a²
so p = k × a²
so that
x = a cosθ
y = a sinθ
dA = adθda
so
I(x) = ∫y²pdA
take limit 0 to 6 for a and o to for θ
I(x) = y²p dA
I(x) = (a sinθ)²(k × a²) adθda
I(x) = k da ×
(sin²θ)dθ
I(x) = k da ×
(1-cos2θ)/2 dθ
I(x) = k ×
I(x) = k × × (
I(x) = k × ×
I(x) = 1444×k × .....................1
and we can say I(x) = I(y) by the symmetry rule
and here I(o) will be I(x) + I(y) i.e
I(o) = 2 × 1444×k ×
I(o) = 3888×k × ......................2
The question isn't clear enough, I think it ask us to calculate the linear speed of a point at the edge of the DVD.
Now let's imagine we're a point at the edge of the DVD, we're undergoing a circular motion. Each minute we will complete a circular track 7200 times, now we need to know the distance we travel each turn. The perimeter of the DVD, a circular object is:
Know recall that:
We now need to know how much distance is traveled during a minute or 60 seconds:
Finally we divide this result with t=60 seconds:
Where the distance units were named units as the length unit is not specified in this exercise.<span />
Now let's imagine we're a point at the edge of the DVD, we're undergoing a circular motion. Each minute we will complete a circular track 7200 times, now we need to know the distance we travel each turn. The perimeter of the DVD, a circular object is:
Know recall that:
We now need to know how much distance is traveled during a minute or 60 seconds:
Finally we divide this result with t=60 seconds:
Where the distance units were named units as the length unit is not specified in this exercise.<span />
Answer: 4.5 V
Explanation:
Given
The voltage of each cell is 1.5 V
If they are connected end to end their potential added to give a higher potential i.e. 1.5+1.5+1.5=4.5 V
