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ycow [4]
3 years ago
13

If you travel 1.7 km north from your house at noon, and at 6:00 PM you travel 5.4 km south, what is your displacement? 3.7 km no

rth 3.7 km south 7.1 km north 7.1 km south
Physics
1 answer:
Yakvenalex [24]3 years ago
6 0

<u>Answer</u>

3.7 Km south


<u>Explanation</u>

The definition of displacement is the distance traveled in a specific direction. It is the vector quantity. We add displacements like the way we add vectors.

Taking the direction towards North to be positive (+1.7 Km), the distance towards south would be negative (-5.4 Km).

Now lets add the two values.

(+1.7) + (-5.4) = 1.7 - 5.4

                    = - 3.7 Km      But negative was towards south.

∴ Answer = 3.7 Km south.


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Use the one-dimensional equation

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An object falling from 50m will have
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Two parallel wires separated by 4.00cm repel each other with a force per unit length of 2.00×10⁻⁴ N/m . The current in one wire
oksian1 [2.3K]

The force will be doubled if direction of one current is reversed and doubled.

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With a distance of 4.00 cm between them, two parallel wires repel one another with a force of 2.00 × 10⁻⁴ N/m. One wire is carrying 5.00 A of current.

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We have, F/L = μ₀ I₁ I₂ / L

Now, we know the force is directly proportional to the product of the current, and the direction of one current is reversed and doubled.

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7 0
1 year ago
dayshawn is traveling at 12 m/s away from the school. dayshaun's mom is looking for him because he is late coming home so she le
vivado [14]

Speed of Dayshawn travelling towards his home is 12 m/s

Speed of her mom towards his school is 5 m/s

They both starts at same time so whenever they will meet on their path the sum of the distance covered by Dayshawn and distance covered by his mom must be equal to the total distance of school and home

Now let say they both meet after "t" time when they starts motion

so we can write the total distance between school and home as

d = v_1*t + v_2*t

here d = 6492 m

v_1 = 12 m/s = speed of dayshawn

v_2 = 5 m/s = speed of his mom

now by solving the above equation

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t = \frac{6492}{17}

t = 381.9 s

so they will meet after 381.9 s from start which will be 3.36 minutes from there start

Also at this time the distance covered by her mom will be

d_2 = v_2*t

d_2 = 5* 381.9 = 1909.4 m

so they will meet at distance 1909.4 m from their home

4 0
3 years ago
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