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Alika [10]
4 years ago
10

Two angles with measures (6x + 60) (90) are supplementary. What is the value of x?

Chemistry
2 answers:
fredd [130]4 years ago
5 0
Supplementary angles add up to 180, so
6x+60+90 = 180 and solve for x
6x= 30
x=5
pishuonlain [190]4 years ago
4 0
Exiting or five because in gem Dos you have to do parentheses first from left to right size 6X +60 is already simplified times 90 now you move your parentheses so you would multiply 16 times 9016×90 whatever that is you would add that to six facts which is not
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Which of the following terms means that metals can be pulled into thin strands or wires? [like copper]
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Answer:

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Explanation:

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33.56 g of fructose (C6H,206) and 18.88 g of water are mixed to obtain a 40.00 ml solution a. What is this solution's density? b
Darina [25.2K]

Explanation:

Mass of fructose = 33.56 g

Mass of water =  18.88  g

Total mass of the solution =  Mass of fructose + Mass of water = M

M = 33.56 g + 18.88  g =52.44 g

Volume of the solution = V = 40.00 mL

Density =\frac{Mass}{Volume}

a) Density of the solution:

\frac{M}{V}=\frac{52.44 g}{40.00 mL}=1.311 g/mL

b) Molar mass of fructose = 180.16 g/mol

Moles of fructose = n_1=\frac{ 33.56 g}{180.16 g/mol}=0.1863 mol

Molar mass of water = 18.02 g/mol

Moles of water= n_2=\frac{ 18.88 g}{18.02 g/mol}=1.0477 mol

Mole fraction of fructose in this solution:\chi_1

\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1863 mol}{0.1863 mol+1.0477 mol}

\chi_1=0.1510

Mole fraction of water = \chi_2=1-\chi_1=0.8490

c) Average molar mass of of the solution:

=\chi_1\times 180.16 g/mol+\chi_2\times 18.02 g/mol

=0.1510\times 180.16 g/mol+0.8490\times 18.02 g/mol=42.50 g/mol

d) Mass of 1 mole of solution = 42.50 g/mol

Density of the solution = 1.311 g/mL

d) Specific molar volume of the solution:

\frac{\text{Average molar mass}}{\text{Density of the mass}}

=\frac{42.50 g/mol}{1.311 g/mL}=32.42 mL/mol

5 0
3 years ago
Can a molecule have polar bonds, but still be a no polar molecule?
My name is Ann [436]

<em><u>A molecule </u></em><em><u>can </u></em><em><u>possess polar bonds and still be nonpolar.</u></em>

I hope this helped. Have a nice day, make sure to take care of yourself. You're loved <3

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4 years ago
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3. 200 ml of 0.2 M HCl is neutralized with 0.1 M
algol [13]

Answer:

  • <u><em>a. 0.1 M</em></u>

Explanation:

By definition, <em>half neutralization</em> is the point at which half of the acid has been neutralized.

The neutralization reaction that you are studying is the acid-base reaction:

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Then, since the starting molarity of the acid (HCl) is 0.2 M, you just need to find half of that concentration:

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So, the answer is the first choice: a. 0.1 M.

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3 years ago
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