229.25 mL of isopropyl alcohol
425.75 mL of water
Explanation:
Knowing that the solution have a 35.0 % (v/v) isopropyl alcohol in water, we can calculate the volume of each component as following.
volume of isopropyl alcohol = (35/100) × solution volume
volume of isopropyl alcohol = 0.35 × 655 mL = 229.25 mL
Now, knowing the volume of isopropyl alcohol we can determine the volume of water.
volume of the solution = volume of isopropyl alcohol + volume of water
volume of water = volume of the solution - volume of isopropyl alcohol
volume of water = 655 mL - 229.25 mL = 425.75 mL
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percent by volume concentration
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Answer:
Nonmetal + Nonmetal —> covalent compound (usually)
Explanation:
Covalent compounds are formed when two nonmetals react with each other.
This problem is providing us with the mass equivalent to one troy ounce. Thus, the troy ounces of gold in one short ton of average Nevada ore is required and found to be the 0.103 otz according to the following dimensional analysis.
<h3>Dimensional analysis</h3>
In chemistry, a raft of problems do not always provide an equation in order to be solved yet dimensional analysis can be applied, so as to obtain the desired amount in the required units.
Thus, since this problem asks for try ounces in an average Nevada ore, which has 3.2 grams of gold per short ton of ore, one can solve the following setup in order to obtain the required answer in otz:

Where the short tons are cancelled out as well as the grams, in order to obtain:

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Here’s the math for your answer, which is 3.3 L HCl