I need help on this math question

(27 thousands 3 hundreds 5 ones) x 10

anyanavicka [17]

Answer:

Two hundred seventy three thousand and fifty .

Step-by-step explanation:

Given : (27 thousands 3 hundreds 5 ones) x 10

Solution:

27 thousands 3 hundreds 5 ones = 27,305

So, $27,305 \times 10$

$273,050$

Periods are counted from last .

The 1st period consists of ones, tens and hundred.

The 2nd period consists of thousand, 10 thousand and 100 thousands.

The 3rd period consists of million, 10 million and 100 million.

So, 273,050 is Two hundred seventy three thousand and fifty

Hence (27 thousands 3 hundreds 5 ones) x 10 is Two hundred seventy three thousand and fifty .

4 0

3 years ago

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Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p

zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

<u>Statement 1: </u>"The pen is 3 feet wider than it is long"

$Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3$

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<u>Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"</u>

$Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y$

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<u>Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."</u>

$Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\$

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<u>Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."</u>

$Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\$

Conclusion:

The systems of equations that can be used to determine the length and width of the pen and the area of the doghouse is given in Option B.

$178=x^2+3x-y\\ \\ -6=4x-3y$

8 0

4 years ago

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Which inequality would result in the shaded solution on the unit circle to the right?

omeli [17]

<h3>Answer: Choice B</h3>

Explanation:

Cosine is positive in quadrants I and IV, but quadrant IV isn't shaded in so we can rule out choice A.

Sine is positive in quadrants I and II. So far it looks like choice B could work. In fact, it's the answer because sin(pi/6) = 1/2 and sin(5pi/6) = 1/2. So if 0 ≤ sin(x) < 1/2, then we'd shade the region between theta = 0 and theta = pi/6; as well as the region from theta = 5pi/6 to theta = pi.

Choice C is ruled out because tangent is positive in quadrants I and III, but quadrant III isn't shaded.

Choice D is ruled out for similar reasoning as choice A. Recall that $\sec(x) = \frac{1}{\cos(x)}$

5 0

3 years ago

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1:0,1+2:0,2+3:0,3...+9:0

s2008m [1.1K]

Answer:

15

Step-by-step explanation:

answeram I righatjfj

6 0

3 years ago

Does a point have no dimension?

nataly862011 [7]

A single point has no dimension.

A line of multiple points will have a length.
Points that creates a plane has two dimensions. length and width
Points that creates a solid shape has three dimensions. length, width, and height

4 0

3 years ago