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3 years ago

What is the density of a 19.3-gram object that displaces 12 cubed centimeters of water

Chemistry

1 answer:

KIM [24]3 years ago

5 0

Answer:

1.608 g/cm3

Explanation:

Formula:

D=m/v

d= density

m= mass

v= volume

Given data:

Mass= 19.3 g

Volume= 12 cm3

The volume of water displaces by object is 12 cm³ which means that object hold the volume of 12 cm³

Now we will put the values in formula:

D=19.3 g/ 12 cm3= 1.608 g/cm3

so the density of object is 1.608 g/cm3

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A scientist measures the speed of sound in a monatomic gas to be 449 m/s at 20∘C. What is the molar mass of this gas?

Ivan

Answer:

The molar mass of the gas is 36.25 g/mol.

Explanation:

To solve this problem, we can use the mathematical relation:

ν = $\sqrt{3RT/M}$

Where, ν is the speed of light in a gas (ν = 449 m/s),

R is the universal gas constant (R = 8.314 J/mol.K),

T is the temperature of the gas in Kelvin (T = 20 °C + 273 = 293 K),

M is the molar mass of the gas in (Kg/mol).

ν = $\sqrt{3RT/M}$

(449 m/s) = √ (3(8.314 J/mol.K) (293 K) / M,

by squaring the two sides:

(449 m/s)² = (3 (8.314 J/mol.K) (293 K)) / M,

∴ M = (3 (8.314 J/mol.K) (293 K) / (449 m/s)² = 7308.006 / 201601 = 0.03625 Kg/mol.

∴ The molar mass of the gas is 36.25 g/mol.

7 0

3 years ago

Which of the following would be most useful in trying to obtain procedural information to replicate an experiment previously pub

Jet001 [13]

Answer: Peer-reviewed journal article is the most useful because the information in them had been carefully scrutinized and aproved by people who are experts in that particular field.

7 0

3 years ago

What happens to carbon compounds in air when heated sufficiently?

madreJ [45]

They may break bonds,form new compounds, new ions etc...

3 0

3 years ago

Which elements have the most properties in common with magnesium

Lunna [17]

The group that magnesium is in has all the elements that are alike to it.
Magnesium is in group 2 which is the alkaline earth metals. So elements similar to it would be calcium, beryllium!

----If you need anymore help in chemistry.....just ask me....im very good at chemistry!

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3 years ago

Oxygen gas can be prepared by heating potassium chlorate according to the following equation: 2KClO3(s)2KCl(s) + 3O2(g) The prod

Ipatiy [6.2K]

Answer:

The number of moles of KClO₃ reacted was 0,15 mol

Explanation:

For the reaction:

2KClO₃(s) → 2KCl(s) + 2O₂(g)

The only gas product is O₂.

Total pressure is the sum of vapor pressure of water with O₂ gas formed. Thus, pressure of O₂ is:

749mmHg - 23,8mmHg = 725,2mmHg

Using gas law:

PV/RT = n

Where:

P is pressure (725,2mmHg ≡ 0,9542atm)

V is volume (5,76L)

R is gas constant (0,082 atmL/molK)

And T is temperature (25°C ≡ 298,15K)

Replacing, number of moles of O₂ are 0,2248 moles

As 2 moles of KClO₃ react with 3 moles of O₂ the moles of KClO₃ that reacted was:

0,2248 mol O₂× $\frac{2 mol KClO_{3}}{3 mol O_{2}}$ = 0,15 mol of KClO₃

I hope it helps!

8 0

3 years ago