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3 years ago

Mention at least two organic compounds synthesized from inorganic substanc

Chemistry

2 answers:

Salsk061 [2.6K]3 years ago

8 0

Answer:

p-Nitro acetanilide. 2-Naphthol aniline dye.

ale4655 [162]3 years ago

8 0

Answer:

1.urea ,and its prepared from liquid ammonia and liquid carbon dioxide

2 .ammonium cyanate

Explanation:

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1. Consider the following: h2so4 2 naoh → na2so4 2 h2o if a 24. 0 ml sample of h2so4 (aq) was neutralized by 20. 0 ml of 0. 125

jasenka [17]

The molarity of the acid sample H₂SO₄ is 0.052M .

<h3>What is Molarity ?</h3>

Molarity (M) is the amount of a substance in a certain volume of solution.

Molarity is defined as the moles of a solute per liters of a solution.

Molarity is also known as the molar concentration of a solution

Now to determine the molarity of the acid sample

V( H₂SO₄) = 24.0 mL in liters = 24.0 / 1000 = 0.024 L

M(H₂SO₄) = ?

V(NaOH) = 20.0 mL = 20.0 / 1000 = 0.02 L

M(NaOH) = 0.125 M

Number of moles NaOH :

n = M x V

n = 0.125 x 0.02

n = 0.0025 moles of NaOH

H₂SO₄(aq) + 2 NaOH(aq) = Na₂SO₄(aq) + 2 H₂O(l)

1 mole H₂SO₄ ---------- 2 mole NaOH

? mole H₂SO₄ ---------- 0.0025 moles NaOH

moles = 0.0025 * 1 / 2

= 0.00125 moles of H₂SO₄

M(H₂SO₄) = n / V

M = 0.00125 / 0.024

= 0.052 M

Therefore the molarity of the acid sample H₂SO₄ is 0.052M .

To know more about molarity

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8 0

2 years ago

n the 1990’s, the Boeing Co. developed a process for treating wastewater from electroplating and printed circuit board manufactu

scZoUnD [109]

Answer:

Final concentrations:

Cu²⁺ = 0

Al³⁺ = 3.13 mmol/L = 84.51 mg/L

Cu = 4.7 mmol/L = 300 mg/L

Al = 0.57 mmol/L = 15.49 mg/L

Explanation:

2Al (s) + 3Cu²⁺ (aq) → 2Al³⁺ (aq) + 3Cu (s)

Al: 27 g/mol ∴ 100 mg = 3.7 mmol

Cu: 63.5 g/mol ∴ 300 mg = 4.7 mmol

3 mol Cu²⁺ _______ 2 mol Al

4.7 mmol Cu²⁺ _____ x

x = 3.13 mmol Al

4.7 mmol of Cu²⁺ will be consumed.

3.13 mmol of Al will be consumed.

4.7 mmol of Cu will be produced.

3.13 mmol of Al³⁺ will be produced.

0.57 mmol of Al will remain.

6 0

3 years ago

In an aqueous solution, 42% of a substance dissociates to release hydronium ions. Which of the following statements is true for

const2013 [10]

Answer: The statement it is a weak acid is true for the substance.

Explanation:

An acid that dissociates completely when dissolved in water to give hydrogen $(H^{+})$ or hydronium $(H_{3}O^{+})$ ions is called a strong acid.

For example, HCl is a strong acid.

$HCl + H_{2}O \rightarrow H_{3}O^{+} + Cl^{-}$

An acid that dissociates partially or weakly when dissolved in water to given hydrogen or hydronium ions is called a weak acid.

For example, $CH_{3}COOH$ is a weak acid.

$CH_{3}COOH \rightleftharpoons CH_{3}COO^{-} + H_{3}O^{+}$

A strong base is a base which when dissolved in water then it dissociates completely to give hydroxide ions.

For example, NaOH is a strong acid.

A weak base is a base which when dissolved in water then it dissociates partially or weakly to give hydroxide ions.

For example, $NH_{3}$ is a weak base.

Hence, in an aqueous solution where 42% of a substance dissociates to release hydronium ions shows that the dissociation is less than 50%. This means that substance is dissociating weakly so, it is a weak acid.

Thus, we can conclude that the statement it is a weak acid is true for the substance.

5 0

3 years ago

Match each of the following terms with the correct definition. Question 6 options: the variable that is measured as data in an e

Aleksandr [31]

The variable that is measured as data in an experiment is 1. the dependent variable.

The variables that are held constant in an experiment are 2. the controlled variables.

The variable that is changed by the experimenter is 5. the independent variable.

A count or measurement recorded during an experiment is 4. quantitative data.

Descriptions or observations during an experiment are 3. qualitative data.

5 0

3 years ago

Read 2 more answers

When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II)

lesya692 [45]

Answer: The mass of lead deposited on the cathode of the battery is 1.523 g.

Explanation:

Given: Current = 62.0 A

Time = 23.0 sec

Formula used to calculate charge is as follows.

$Q = I \times t$

where,

Q = charge

I = current

t = time

Substitute the values into above formula as follows.

$Q = I \times t\\= 62.0 A \times 23.0 sec\\= 1426 C$

It is known that 1 mole of a substance tends to deposit a charge of 96500 C. Therefore, number of moles obtained by 1426 C of charge is as follows.

$Moles = \frac{1426 C}{96500 C/mol}\\= 0.0147 mol$

The oxidation state of Pb in $PbSO_{4}$ is 2. So, moles deposited by Pb is as follows.

$Moles of Pb = \frac{0.0147}{2}\\= 0.00735 mol$

It is known that molar mass of lead (Pb) is 207.2 g/mol. Now, mass of lead is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\ 0.00735 = \frac{mass}{207.2 g/mol}\\mass = 1.523 g$

Thus, we can conclude that the mass of lead deposited on the cathode of the battery is 1.523 g.

3 0

3 years ago

Mention at least two organic compounds synthesized from inorganic substanc​

Mention at least two organic compounds synthesized from inorganic substanc