Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
sin²x + cos²x = 1 , then
sin²x = 1 - cos²x and cos²x = 1 - sin²x
Consider the left side
← expand numerator/denominator using FOIL
= 
= 
= 
= 
= cot²A = right side , thus proven
Considering the slopes of the segments, the correct option is:
D. No, because the triangle ABC doesn't have a pair of perpendicular sides.
<h3>When are lines parallel, perpendicular or neither?</h3>
The slope, given by <u>change in y divided by change in x</u>, determines if the lines are parallel, perpendicular, or neither, as follows:
- If they are equal, the lines are parallel.
- If their multiplication is of -1, they are perpendicular.
- Otherwise, they are neither.
Here, we have to find if there are perpendicular segments, that is, if two slopes multiplied have a value of -1, then:
- mAB = (-7 - 9)/(11 - 1) = -8/5.
- mAC = (3 - 9)/(-9 - 1) = 3/5.
- mBC = (3 - (-7))/(-9 - 11) = -1/2.
No sides are perpendicular, hence option D is correct.
More can be learned about slopes at brainly.com/question/20847660
#SPJ1
Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24
Slope is rise over run so
(21-18)/(6-3), 3/3=1, slope is 1
plug in to find b value
18=3+b, b=15
ANSWER: y=x+15
The answer would be 144 inches, found by multiplying the length of the paper by the width.
