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atroni [7]
3 years ago
8

A tree has a circumference of 16 ft. Calculate the volume of wood it contains if the tree is 10ft tall. Round your answer to the

nearest whole number.
a0 cubic feet
Mathematics
1 answer:
Veronika [31]3 years ago
7 0

Answer:

Step-by-step explanation:

The circumference of the tree is the distance around the tree's circular top. The formula for determining the circumference of a circle is expressed as

Circumference = 2πr

If the tree has a circumference of 16 ft, it means that

2πr = 16

πr = 16/2 = 8

r = 8/π

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

if the tree is 10ft tall, then the volume of wood it contains is

Volume = π × (8/π)² × 10

Volume = 64/π × 10

Volume = 64/3.14 × 10

Volume = 204 cubic feet

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the length of a rectangle is 3cm more than the width. find the length and the width if the perimeter of the rectangle is 98cm.
laila [671]

The perimeter of a rectangle is <u>length + length + width + width</u>.

We know that the length of a rectangle is 3cm more than its width, which gives us the equation:  (l for length and w for width)

l = 3 + w

We also know that the perimeter of the rectangle is 98cm, which gives us the equation:

98 = 2l + 2w         (equation for perimeter of a rectangle as noted above)

We can divide both sides of this equation by 2 to get:

49 = l + w

Now we'll stick l = 3 + w into the above equation, which gives us:

49 = 3 + w + w

which simplifies to 49 = 3 + 2w.

Now we'll subtract 3 from both sides:

49 - 3 = 46

3 + 2w - 3 = 2w

which gives us 46 = 2w.

Dividing both sides by 2 gives us 23 = w.

Substituting w = 23 into the equation l = 3 + w gives us:

l = 3 + 23

l = 26cm.

Let's check our answer.  26cm is 3cm more than 23cm.  26cm + 26cm + 23cm + 23cm gives us 98cm.  The length is 26cm and the width is 23cm.


7 0
3 years ago
PLEASE SOVEL THIS I WILL GIVE OUT 20 POINT
Anettt [7]

9514 1404 393

Answer:

  21.25 seconds

Step-by-step explanation:

In miles per second, the speed of the jet is ...

  (720 mi/h)/(3600 s/h) = 1/5 mi/s

The speed of the sound is the same:

  (1 mi)/(5 s) = 1/5 mi/s

Then the rate of closure between the airplane and the sound is ...

  (1/5 mi/s) +(1/5 mi/s) = 2/5 mi/s

To find the time required to close a gap of 8 1/2 miles, we can use the relation ...

  time = distance/speed

  time = (8.5 mi)/(0.4 mi/s) = 21.25 s

The pilot will hear the thunder 21.25 seconds after the flash.

5 0
3 years ago
Can someone please help me? :(
Anit [1.1K]

Answer:

____________________________________

\large{ \tt{ \star \: S \: O \: L \: U \: T \: I \: O \: N : }}

\large{ \boxed{ \tt{♡ \: VOLUME \:  = l \:  \times b  \:  \times h}}}

\longrightarrow \: 4 \frac{1}{3}  \times 3 \frac{1}{3}  \times 4

\longrightarrow \:  \frac{13}{3}  \times  \frac{10}{3}  \times 4

\longrightarrow \:  \frac{540}{9}

\longrightarrow \tt \: 57 \frac{7}{9}  \: ft ^{3}

  • Our final answer is 57 7 / 9 ft^3 .

- HappY LearninG ^_________^

4 0
2 years ago
Help me answer these questions please 15, 19 and 20 please​
SpyIntel [72]

Answer:

15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

Step-by-step explanation:

We are to find the derivative of the questions pointed out.

15) K(t) = 5(5^(t)) - 2(3^(t))

Using implicit differentiation, we have;

K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P(w) = 2e^(w) - (2^(w))/5

P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)

Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)

Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

7 0
3 years ago
if gh¢400.00 is deposited at a bank at 10% per annum compounded quarterly, how long will it take the deposit to double it value.
Semenov [28]

Answer:

~ 7 years

Step-by-step explanation:

2 = (1 + .1/4)^(4t)

2 = (1.025)^(4t)

Take the log of both sides

log2 = 4t * log1.025

divide both sides by log1.025

log2/log1.025 = 4t

28.07103452593863 = 4t

Divide both sides by 4

7.017758631484657 = t

~ 7 years

8 0
3 years ago
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