The graph of y = ax 2 + bx + c is shown below. Determine the solution set of 0 = ax 2 + bx + c.
2 answers:
Answer:
the solution set of the quadratic equation is
Step-by-step explanation :
we know that
The zero's of a quadratic function are the values of x when the value of the function is equal to zero
so
In this problem observing the graph
The zero's of the function are the points and
therefore
the solution set of the quadratic equation is
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Answer:
Step-by-step explanation:
A standard polynomial in factored form is given by:
Where <em>p</em> and <em>q</em> are the zeros.
We want to find a third-degree polynomial with zeros <em>x</em> = 2 and <em>x </em>= -8i and equals 320 when <em>x </em>= 4.
First, by the Complex Root Theorem, if <em>x</em> = -8i is a root, then <em>x </em>= 8i must also be a root.
Therefore, we acquire:
Simplify:
Expand the second and third factors:
Hence, our function is now:
It equals 320 when <em>x</em> = 4. Therefore:
Solve for <em>a</em>. Evaluate:
So:
Our third-degree polynomial equation is:
To simplify these expressions, you can either use a calculator (which I'm assuming your teacher doesn't want you to do) or FOIL (distribute).
The first one would be:
The second one would be:
The first one would be:
The second one would be: