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Anestetic [448]
3 years ago
14

A bag contains 15 coins consisting of quarters and dimes. The total value of the coins is $2.55. Which system of equations can b

e used to
determine the number of quarters, q, and the numbers of dimes, d, in the bag?
Mathematics
1 answer:
denis23 [38]3 years ago
5 0

Answer: d+q= 2.55

or d=15+q

I believe this is how you do it

Step-by-step explanation:

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The heat developed in an electric wire varies jointly as the wires resistance, the time the current flows, & the square of t
never [62]

Answer:

4 ohms

Step-by-step explanation:

The question is "In two minutes a current of 5 amps develops 1,200 heat units in a wire of 8 ohms resistance. What resistance does a similar wire have, which develops 6,000 heat units with a current of 10 amps in 5 minutes?"

Current, I₁ = 5 A

Heat, Q₁ = 1200 units

Resistance, R₁ = 8 ohms

Time, t₁ = 2 min = 120 s

New heat, Q₂ = 6000 units

Current, I₂ = 10 A

New time, t₂ = 5 min = 300 s

We need to find the new resistance.

Heat developed is given by :

Q=I^2Rt

\dfrac{Q_1}{I_1^2R_1t_1}=\dfrac{Q_2}{I_2^2R_2t_2}\\\\R_2=\dfrac{Q_2\times I_1^2R_1t_1}{Q_1I_2^2t_2}\\\\R_2=\dfrac{6000\times 5^2\times 8\times 120}{1200\times 10^2\times 300}\\\\=4\ \Omega

So, the new resistance is 4 ohms.

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2 years ago
Use the probability distribution table to answer the question.
ludmilkaskok [199]

Answer:

1. 0.21 like that has happened

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Find the length of each side of an equilateral triangle with perimeter 60 inches.
slava [35]

Answer:

20

Step-by-step explanation:

60 divided into 3 = 20 since all sides are equal then you get 20 for each side.

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3 years ago
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Sholpan [36]

Answer:

C. 2-√3

Step-by-step explanation:

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2 years ago
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In the exercise, X is a binomial variable with n = 5 and p = 0.2. Compute the given probability. Check your answer using technol
Ronch [10]

Answer:

0.0512

Step-by-step explanation:

We are told in the question that X isa Binomial variable. Hence we solve this question, using the formula for Binomial probability.

The formula for Binomial Probability = P(x) = (n!/(n - x) x!) × p^x × q ^n - x

In the above question,

x = 3

n = 5

p = probability for success = 0.2

q = probability for failures = 1 - 0.2 = 0.8

P(x) = (n!/(n - x) x!) × p^x × q ^n - x

P(3) = (5!/(5 - 3) 3!) × 0.2^3 × 0.8^5-3

P(3) =( 5!/2! × 3!) × 0.2³ × 0.8²

P(3) = 10 × 0.008 × 0.64

P(3) = 0.0512

6 0
3 years ago
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