Answer:
The speed of the stone just before it hits the ground is 18.54 m/s
Explanation:
Given that,
Initial speed of the stone, u = 8 m/s
The stone is thrown downward from a height of 14 m
We need to find the speed of the stone just before it hits the ground. It can be calculated using third equation of motion as :
v is the speed of the stone just before it hits the ground
v = 18.54 m/s
So, the speed of the stone just before it hits the ground is 18.54 m/s. Hence, this is the required solution.
Given :
A wrecking ball of mass 500 kg hangs form a crane by a cable of length 25 m
this wrecking ball is released from an angle of 40 degrees.
To Find :
The height from the lowest point of the arc.
Solution :
From the attached image we have to find the value of h.
So,
Hence, this is the required solution.
Answer:
A )
b) There are approximately 100,000,000 atoms on the 1.32 cm lines
Explanation:
To ensure the accuracy of our answer, we will have to make sure we work in the appropriate units.
A
To convert to inches, we can use this factor.
1 m = 39.3701 inches
Therefore =
B
To find the number of atoms on a 1.32 cm line, we will first of all need to convert 1.32 cm to meters.
1.32 cm = 0.0132 metres (divided 1.32 by 100 to convert to metres)
Assuming all the atoms are arranged side by side, with their edges touching on the 0.0132m line, the number of atoms present will be
= 100,000,000 atoms
when sled just start to move the force on the sled will be equal to the static friction
So here we need to find the value of static friction
We know that
m = 30 kg
now we know that normal force on the block is counterbalanced by weight of the block
now in order to find the friction force we can use
so it requires 59 N of force to move the sled