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pickupchik [31]
4 years ago
8

A compressed gas cylinder containing 1.50 mol methane has a volume of 3.30 L. What pressure does the methane exert on the walls

of the cylinder if its temperature is 25°C?

Physics
2 answers:
sweet-ann [11.9K]4 years ago
4 0

Answer:

P=11.126 atm

Explanation:

We are given that a compressed gas cylinder containing 1.50 mol methane

Volume of methane in a gas cylinder =3.3 L

Temperature =25^{\circ}=25+273.15=298.15 K

We have to find the pressure exert by gas on cylinder

Using ideal gas equation

PV =nRT

Where R= gas constant=0.0821 L-atm/K mol

Substitute all given values

Then we get

P\times 3.3=1.5\times 0.0821\times 298.15

P=\frac{36.717}{3.3}

P=11.126 atm

Hence, the pressure exert by the gas on cylinder =11.126 atm

DaniilM [7]4 years ago
3 0

The pressure of the gas is about 11.1 atm

\texttt{ }

<h3>Further explanation</h3>

The Ideal Gas Law and Work formula that needs to be recalled is:

\boxed {PV = nRT}

\boxed { W = P \Delta V }

<em>where:</em>

<em>W = Work ( J )</em>

<em>P = Pressure ( Pa )</em>

<em>V = Volume ( m³ )</em>

<em>n = number of moles ( moles )</em>

<em>R = Gas Constant ( 8.314 J/mol K )</em>

<em>T = Absolute Temperature ( K )</em>

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

amount of substance = n = 1.50 mol

volume of gas = V = 3.30 L

temperature of gas = T = 25 + 273 = 298 K

gas constant = R = 0.0821 L.atm/mol.K

<u>Asked:</u>

pressure of gas = P = ?

<u>Solution:</u>

PV = n R T

P = n R T \div V

P = 1.50 \times 0.0821 \times 298 \div 3.30

P \approx 11.1 \texttt{ atm}

\texttt{ }

<h3>Conclusion :</h3>

The pressure of the gas is about 11.1 atm

\texttt{ }

<h3>Learn more</h3>
  • Minimum Coefficient of Static Friction : brainly.com/question/5884009
  • The Pressure In A Sealed Plastic Container : brainly.com/question/10209135
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Pressure

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