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4 years ago

What is the empirical formula for a compound if a sample contains 3.72 g of P and 21.28 g of Cl

1 answer:

6 0

M(P)=3.72 g
M(P)=31 g/mol

m(Cl)=21.28 g
M(Cl)=35.5 g/mol

n(P)=m(P)/M(P)
n(P)=3.72/31=0.12 mol

n(Cl)=m(Cl)/M(Cl)
n(Cl)=21.28/35.5=0.60 mol

P : Cl = 0.12 : 0.60 = 1 : 5

PCl₅ - is the empirical formula

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Answer: The molality of barium chloride solution is 0.289 m

Explanation:

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Volume of water = 748 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{748mL}\\\\\text{Mass of water}=(1g/mL\times 748mL)=748g$

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

$m_{solute}$ = Given mass of solute (barium chloride) = 45.0 g

$M_{solute}$ = Molar mass of solute (barium chloride) = 208.23 g/mol

$W_{solvent}$ = Mass of solvent (water) = 748 g

Putting values in above equation, we get:

$\text{Molality of barium chloride solution}=\frac{45\times 1000}{208.23\times 748}\\\\\text{Molality of barium chloride solution}=0.289m$

Hence, the molality of barium chloride solution is 0.289 m

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3 years ago

Identify whether longhand notation or noble-gas notation was used in each case below. Potassium (K): 1s22s22p63s23p64s1

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Explanation:

Long-hand notation of representing electronic configuration is defined as the arrangement of total number of electrons that are present in an element.

Noble-gas notation of representing electronic configuration is defined as the arrangement of valence electrons in the element. The core electrons are represented as the previous noble gas of the element that is considered.

The given electronic configuration of potassium (K): $1s^22s^22p^63s^23p^64s^1$

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3 years ago

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3 years ago

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