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3 years ago

A line has a slope of 5 and a y-intercept of -2.

Chemistry

1 answer:

KiRa [710]3 years ago

4 0

Answer:

+T919919 mean the x- intercept of the line

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Which of these factors should remain constant in a simulation of natural

musickatia [10]

A is your answer The ratio of females to males

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1 year ago

In what state of matter do molecules bounce off one another rapidly and freely

lions [1.4K]

I think its gas i forgot

6 0

2 years ago

If the pressure in the room is 759.2 torr and the vapor pressure of water is 23.8 torr, what is the pressure of hydrogen gas in

Gwar [14]

The partial pressure of Hydrogen gas can directly be calculated by simply taking the difference of the overall pressure and the vapour pressure of water. That is:

P (H2 gas) = 759.2 torr – 23.8 torr

6 0

3 years ago

Read 2 more answers

Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: PCl3(g)+Cl2(g)⇌PCl5(g). A 7.5-L gas vess

Tpy6a [65]

Answer:

The equilibrium constant in terms of concentration that is, $K_c=3.6243\times 10^{3}$ .

Explanation:

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

The relation of $K_c\& K_p$ is given by:

$K_p=K_c(RT)^{\Delta n_g}$

$K_p$ = Equilibrium constant in terms of partial pressure.=98.1

$K_c$ = Equilibrium constant in terms of concentration =?

T = temperature at which the equilibrium reaction is taking place.

R = universal gas constant

$\Delta n_g$ = Difference between gaseous moles on product side and reactant side= $n_{g,p}-n_{g.r}=1-2=-1$

$98.1=K_c(RT)^{-1}$

$98.1 =\frac{K_c}{RT}$

$K_c=98.1\times 0.0821 L atm/mol K\times 450 K=3,624.30=3.6243\times 10^{3}$

The equilibrium constant in terms of concentration that is, $K_c=3.6243\times 10^{3}$ .

5 0

3 years ago

Read 2 more answers

In a mixture of 2 ideal gases, A and B, PA = 0.2PB, what is the mole fraction of A?

Alborosie

Answer:

0.1667

Explanation:

Hello,

Dalton's law defines:

$y_i=\frac{P_i}{P_T}$

A total pressure is:

$P_T=P_A+P_B$

So, for A (solving for $P_A$ in the previous equation, we get:

$y_A=\frac{P_A}{P_A+P_B}$

Since $P_A=0.2P_B$ , we obtain:

$y_A=\frac{P_A}{P_A+P_A/0.2}\\y_A=\frac{1}{6}\\y_A=0.1667$ }

Best regards.

7 0

3 years ago