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Maurinko [17]
2 years ago
10

What is the percentage by volume of 30.0 mL ethanol (C2H6O) dissolved in 150.0 mL water (H2O)?

Chemistry
1 answer:
NeX [460]2 years ago
5 0

Answer: 16.7 %

Explanation:

\frac{30.0}{150.0+30.0}=\boxed{16.7\%}

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Changes in a state of matter include?
o-na [289]

Answer: melting, freezing, sublimation, deposition, condensation, and vaporization

4 0
3 years ago
Read 2 more answers
Calculate the number of joules of heat energy needed to increase the temperature of 25.0 g of metal from 21.0 ºC to 80.0 ºC. The
Harman [31]

Answer:

Q = 768.47 J

Explanation:

Given that,

Mass of the metal, m = 25 g

Initial temperature, T₁ = 21.0 ºC

Final temperature, T₂ = 80.0 ºC

The specific heat of the metal is 0.521 J/gºC.

We know that the heat released due to the change in temperature is given by :

Q=mc\Delta T\\\\=25\times 0.521\times (80-21)\\Q=768.47\ J

Hence, 768.47 J of heat energy will be needed.

7 0
3 years ago
When agno3 was added to test tube d it reacted with cl to form agcl precipitate. Did this result in a shift to the right or the
AlekseyPX

Answer:

Reaction will move rightwards.

Explanation:

Hello there!

In this case, according to the proposed question, it turns out possible for us to  figure out the effect of the addition of silver nitrate, by using the following representative equation for the formation of the silver chloride precipitate:

Ag^+(aq)+Cl^-(aq)\rightleftharpoons AgCl(s)

Now, due to the addition of silver nitrate, we will be actually adding silver ions to the solution, which means that, in terms of the Le Ch atelier's principle, the reaction will shift to the right towards the formation of more silver chloride precipitate.

Best regards!

4 0
3 years ago
(1.7m - 2) + (2m – 4)
Pavel [41]

Answer: 3.7 m − 6

Explanation: Simplify the expression.

brainliest or a thank you pls :)) <3

6 0
3 years ago
How much of a 0.250 M lithium hydroxide is required to neutralize 20.0 mL of 0.345M chlorous acid?
Bumek [7]

Answer:

27.6mL of LiOH 0.250M

Explanation:

The reaction of lithium hydroxide (LiOH) with chlorous acid (HClO₂) is:

LiOH + HClO₂ → LiClO₂ + H₂O

<em>That means, 1 mole of hydroxide reacts per mole of acid</em>

Moles of  20.0 mL = 0.0200L of 0.345M chlorous acid are:

0.0200L ₓ (0.345mol / L) = <em>6.90x10⁻³ moles of HClO₂</em>

To neutralize this acid, you need to add the same number of moles of LiOH, that is 6.90x10⁻³ moles. As the LiOH contains 0.250 moles / L:

6.90x10⁻³ moles ₓ (1L / 0.250mol) = 0.0276L of LiOH =

<h3>27.6mL of LiOH 0.250M</h3>
6 0
3 years ago
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