Question

Acetone, a common solvent, has density 0.79g/cm3 at 20 degrees celcius. What is the volume of 85.1g of acetone at 20 degrees celcius? What is the mass of 125mL of acetone at 20degrees celcius? Show your calculations.

Answer 1

Answer: The volume of acetone having 85.1 g of mass is $107.72cm^3$ . The mass of acetone having volume of 125 mL is 98.75 g.

Explanation:

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$      ......(1)

• For the calculation of volume:

Density of acetone = $0.79g/cm^3$

Mass of acetone = 85.1 g

Putting values in equation 1, we get:

$0.79g/cm^3=\frac{85.1g}{\text{Volume of acetone}}\\\\\text{Volume of acetone}=107.72cm^3$

The volume of acetone for the mass of 85.1 g is $107.72cm^3$

• For the calculation of mass:

We are given:

Density of acetone = $0.79g/cm^3$

Volume of acetone = $125mL=125cm^3$      (Conversion factor: $1mL=1cm^3$ )

Putting values in equation 1, we get:

$0.79g/cm^3=\frac{\text{Mass of acetone}}{125cm^3}\\\\\text{Mass of acetone}=98.75g$

Hence, the mass of acetone for the volume of 125 mL is 98.75 g

Answer 2

1)

a)

D = 0.79 g/cm³           m = 85.1 g

D = m / V

0.79 = 85.1 / V

V = 85.1 / 0.79 => 107.72 cm³
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b) D = m / V

0.79 = m / 125

m = 0.79 x 125 => 98.75 g
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hope this helps!