Ask question

Ask question

All categories

2 years ago

8

Acetone, a common solvent, has density 0.79g/cm3 at 20 degrees celcius. What is the volume of 85.1g of acetone at 20 degrees cel

cius? What is the mass of 125mL of acetone at 20degrees celcius? Show your calculations.

2 answers:

Wittaler [7]2 years ago

8 0

<u>Answer:</u> The volume of acetone having 85.1 g of mass is $107.72cm^3$ . The mass of acetone having volume of 125 mL is 98.75 g.

<u>Explanation:</u>

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$ ......(1)

<u>For the calculation of volume:</u>

Density of acetone = $0.79g/cm^3$

Mass of acetone = 85.1 g

Putting values in equation 1, we get:

$0.79g/cm^3=\frac{85.1g}{\text{Volume of acetone}}\\\\\text{Volume of acetone}=107.72cm^3$

The volume of acetone for the mass of 85.1 g is $107.72cm^3$

<u>For the calculation of mass:</u>

We are given:

Density of acetone = $0.79g/cm^3$

Volume of acetone = $125mL=125cm^3$ (Conversion factor: $1mL=1cm^3$ )

Putting values in equation 1, we get:

$0.79g/cm^3=\frac{\text{Mass of acetone}}{125cm^3}\\\\\text{Mass of acetone}=98.75g$

Hence, the mass of acetone for the volume of 125 mL is 98.75 g

RoseWind [281]2 years ago

4 0

1)

a)

D = 0.79 g/cm³ m = 85.1 g

D = m / V

0.79 = 85.1 / V

V = 85.1 / 0.79 => 107.72 cm³
____________________________________________
b) D = m / V

0.79 = m / 125

m = 0.79 x 125 => 98.75 g
____________________________________________

hope this helps!

You might be interested in

PLS HELP STOICHIOMETRY/CHEM!!!

Mariulka [41]

The molecular formula of the compound that we are required to find is the compound C4H8O8

<h3>What is empirical formula?</h3>

The empirical formula of a compound is a formula that shows the ratio of each atom present in the compound. We will start by dividing each mass with the relative atomic mass of the atom.

Carbon - 48.38 g/12 Hydrogen - 6.74 g/1 Oxygen - 53.5 g/16

Carbon - 4 Hydrogen - 6.74 Oxygen - 8.9

Dividing through by the lowest ratio;

Carbon - 4/4 Hydrogen - 6.74/4 Oxygen 8.9/4

Carbon 1 Hydrogen 2 Oxygen 2

The empirical formula is CH2O2.

To obtain the molecular formula; brainly.com/question/11588623

[12 + 2 + 32]n = 180

n = 180/[12 + 2 + 32]

n =4

The compound C4H8O8

Learn more about empirical formula:

7 0

2 years ago

In which are the ionic solids ranked in order of increasing melting point?

abruzzese [7]

Answer:A

Explanation:

The melting points of solids depend in the relative sizes of ions in the ionic lattice. The smaller the relative sizes of the ions, the higher the lattice energy and the stronger the lattice hence higher melting point. Comparing relative ionic sizes, fluoride ion is lesser in size than chloride ion hence NaF has a higher melting point than NaCl.

7 0

3 years ago

Burning a compound of calcium, carbon, and nitrogen in oxygen in a combustion train generates calcium oxide , carbon dioxide , n

mylen [45]

The question is incomplete, here is the complete question:

Burning a compound of calcium, carbon, and nitrogen in oxygen in a combustion train generates calcium oxide (CaO), carbon dioxide $(CO_2)$ , nitrogen dioxide $(NO_2)$ , and no other substances. A small sample gives 2.389 g CaO, 1.876 g $CO_2$ , and 3.921 g $NO_2$ Determine the empirical formula of the compound.

<u>Answer:</u> The empirical formula for the given compound is $CaCN_2$

<u>Explanation:</u>

The chemical equation for the combustion of compound having calcium, carbon and nitrogen follows:

$Ca_xC_yN_z+O_2\rightarrow CaO+CO_2+NO_2$

where, 'x', 'y' and 'z' are the subscripts of calcium, carbon and nitrogen respectively.

We are given:

Mass of CaO = 2.389 g

Mass of $CO_2=1.876g$

Mass of $NO_2=3.921g$

We know that:

Molar mass of calcium oxide = 56 g/mol

Molar mass of carbon dioxide = 44 g/mol

Molar mass of nitrogen dioxide = 46 g/mol

<u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 1.876 g of carbon dioxide, $\frac{12}{44}\times 1.876=0.5116g$ of carbon will be contained.

<u>For calculating the mass of nitrogen:</u>

In 46 g of nitrogen dioxide, 14 g of nitrogen is contained.

So, in 3.921 g of nitrogen dioxide, $\frac{14}{46}\times 3.921=1.193g$ of nitrogen will be contained.

<u>For calculating the mass of calcium:</u>

In 56 g of calcium oxide, 40 g of calcium is contained.

So, in 2.389 g of calcium oxide, $\frac{40}{56}\times 2.389=1.706g$ of calcium will be contained.

To formulate the empirical formula, we need to follow some steps:

<u>Step 1:</u> Converting the given masses into moles.

Moles of Calcium = $\frac{\text{Given mass of Calcium}}{\text{Molar mass of Calcium}}=\frac{1.706g}{40g/mole}=0.0426moles$

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.5116g}{12g/mole}=0.0426moles$

Moles of Nitrogen = $\frac{\text{Given mass of Nitrogen}}{\text{Molar mass of Nitrogen}}=\frac{1.193g}{14g/mole}=0.0852moles$

<u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0426 moles.

For Calcium = $\frac{0.0426}{0.0426}=1$

For Carbon = $\frac{0.0426}{0.0426}=1$

For Nitrogen = $\frac{0.0852}{0.0426}=2$

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of Ca : C : N = 1 : 1 : 2

Hence, the empirical formula for the given compound is $CaCN_2$

3 0

3 years ago

The atomic number of aluminum is 13. What is the correct designation of the electron configuration of aluminum?.

Svetlanka [38]

Answer:

Its 1s22s22p63s23p1 ik it looks a lil goofy but i think its right

Explanation:

3 0

1 year ago

A mixture of He , Ar , and Xe has a total pressure of 3.00 atm . The partial pressure of He is 0.200 atm , and the partial press

yaroslaw [1]

The partial pressure of Xe is 2.60atm

The sum of the partial pressures is equal to the total pressure. Ptotal = P1 + P2 + P3... .To calculate the partial pressure of one of the components of a mixture, subtract the sum of known partial pressures of the other components from the total pressure.

Given the values of

PHe=0.20 atm

PAr=0.20 atm

Ptotal=3.00 atm

We need to find PXe

Solution: Determine the sum of the partial pressures of helium and argon, then subtract the sum from the total pressure.

PHe+PAr =0.20 atm + 0.20=0.400 atm

PXe=3.00atm−0.400=2.60 atm

Each gas that makes up a mixture of gases has a partial pressure, which is the notional pressure of that gas as if it alone filled the original combination's complete volume at the same temperature.

According to Dalton's Law, a perfect gas mixture's total pressure equals the sum of its constituent gases' individual partial pressures.

The thermodynamic activity of a gas's molecules is gauged by its partial pressure.

Gases react, disperse, and dissolve based on their partial pressures rather than the concentrations they have in liquids or other gas combinations.

This general characteristic of gases holds true in biological chemical interactions involving gases.

Hence the partial pressure of Xe is 2.60atm

Learn more about partial pressure here

brainly.com/question/19813237

#SPJ4

5 0

2 years ago