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cluponka [151]
3 years ago
5

Logs sometimes float vertically in a lake because one end has become water-logged and denser than the other. What is the average

density of a uniform-diameter log that floats with 29.1 % of its length above water?
Physics
1 answer:
Helga [31]3 years ago
4 0

Answer:

709 kg/m³

Explanation:

Applying the expression obtained from Archimedes Principle as:

\% of\ the\ fraction\ submerged=\frac {\rho_{object}}{\rho_{liquid}}\times 100

Given :

Percentage of the log above water = 29.1%

Percentage of the log of the water submerged = 100-29.1 % = 70.9%

Density of water = 1000 kg/m³

So,

70.9 \% =\frac {\rho_{object}}{1000}\times 100

<u>The average density of the log = 709 kg/m³</u>

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