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Amiraneli [1.4K]

2 years ago

15

The fourth grade students from last year lost 2345356 pencils. The fourth grade students from this year have already lost 34553

pencils. How many pencils have been lost so far?

1 answer:

inysia [295]2 years ago

7 0

Answer:

2379909 pencils. Hope this helps!

Step-by-step explanation:

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What would be the reasonable estimate for value of m 31+m=307

abruzzese [7]

M= 276 31+276=307.
307-31=276 that’s how I found M

8 0

2 years ago

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Let f(x) = 2x^2 +3x-4 find f(3h)

azamat

A

substitute x = 3h into f(x)

f(3h) = 2(3h)² + 3(3h) - 4 = (2 × 9h²) + 9h - 4 = 18h² + 9h - 4

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Which proportion can be used to find the arc length, s, in units?

Alinara [238K]

Answer:

Option B

Step-by-step explanation:

Formula to be used to calculate the length of an arc,

Length of arc = $\frac{\theta}{360}(2\pi r)$

Here, θ = Angle subtended at the center by the arc

r = radius of the circle

By substituting values in the formula,

s = $\frac{150}{360}(2\pi )(42)$

$\frac{s}{2\times 42\pi }=\frac{150}{360}(\frac{2\times 24\pi }{2\times 24\pi } )$

$\frac{s}{84 \pi }=\frac{150}{360}$

Therefore, Option B will be the answer.

5 0

3 years ago

A line has the slope of -1 and a y-intercept of -2. What is an equation that could represent this line?

Shkiper50 [21]

Sorry but I can’t :( I’m 2 dumb ♥️

3 0

2 years ago

A 40 amp fuse carries a temporary 9 % current overload. How many

ziro4ka [17]

Answer:

43.6 amp

Step-by-step explanation:

Given

A 40 amp fuse carries a temporary 9 % current overload.

9% current overload means that whatever will be the normal current carrying capacity of fuse, during overload it carries 9% more than that.

Current carrying capacity of fuse is 40 amp.

during overload it carries 9% more

over load current = 9% of 40 amp = 9/100 *40 = 3.6 amp

total current flowing through fuse during overload = 40 amp + 3.6 amp

= 43.6 amp (answer)

7 0

3 years ago