Answer:
.
Start color: yellowish-green.
End color: dark purple.
Assumption: no other ion in the solution is colored.
Explanation:
In this reaction, chlorine gas
oxidizes iodine ions
to elemental iodide
. At the same time, the chlorine atoms are converted to chloride ions
.
Fluorine, chlorine, bromine, and iodine are all halogens. They are all found in the 17th column of the periodic table from the left. One similarity is that their anions are not colored. However, their elemental forms are typically colored. Besides, moving down the halogen column, the color becomes darker for each element.
Among the reactants of this reaction,
is colorless. If there's no other colored ion, only the yellowish-green hue of
would be visible. Hence the initial color of the reaction would be the yellowish-green color of
.
Similarly, among the products of this reaction,
is colorless. If there's no other colored ion, only the dark purple hue of
would be visible. Hence the initial color of the reaction would be the dark purple color of
.
The climate would become colder...
Cl is highly electronegative and will actually pull away 1 electron from sodium, forming an ionic bond.
Answer:
Explanation:
If we look at the structure of 1-Bromopropane; we will see that it is a derivative of alkane family by the the substitution of an alkyl group. The position of the Bromine in the propane is 1, making 1-Bromopropane a primary alkyl-halide.
Primary alkyl - halide undergo SN2 mechanism. This nucleophilic reaction needs to be a strong alkyl halide , such as 1-Bromopropane used otherwise it will result to a reactive mechanism if a weak electrophile is used.
However, the critical and the main objective here is to Draw the major substitution product if the reaction proceeds in good yield. If no reaction is expected or yields will be poor, draw the starting material in the box. If a charged product is formed, be sure to draw the counterion.
The attached diagrams portraying this notions is shown in the attached file below.