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ikadub [295]
3 years ago
10

What two of aristotle’s main ideas did galileo discredit?

Physics
1 answer:
polet [3.4K]3 years ago
5 0
Heavy objects fall faster than lighter ones and that no more force is needed on a moving object
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A wave has a wavelength of 20 mm and a frequency of 5 Hz what is the speed?
yKpoI14uk [10]
The answer is 100mm/s. I hope this helps :)

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Without sea otters, sea urchins would overgraze on kelp beds, dramatically changing the marine community. true/false
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Near the equator, the patterns of convection currents are called ________.
tatyana61 [14]
<span>Near the equator, the patterns of convection currents are called Hadley Cells.
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Hadley Cells refers to the low-latitude overturning movements that have air increasing at the equator and air dropping at roughly latitude of 30 degree and these cells are also responsible for the trade winds in the Tropics and control low-latitude patterns of weather.

8 0
3 years ago
A skater increases her velocity from 2.0 m/s to 10.0 m/s in 3.0 seconds. What is the skater's acceleration?
geniusboy [140]

As change is velocity is

<span>Δv=<span>10 m s<span>−1</span></span>−<span>2 m s<span>−1</span></span>=<span>8 m s<span>−1</span></span></span>

and time taken is 3 seconds so acceleration is

<span>acceleration=<span>change in velocitychange in time</span></span>

So

<span>a=<span><span>8 m s<span>−1</span></span>3 s</span>=<span>2.7 m s<span>−<span>2</span></span></span></span>

8 0
3 years ago
Earth's neighboring galaxy, the Andromeda Galaxy, is a distance of 2.54×10^7 light-years from Earth. If the lifetime of a human
kupik [55]

Answer:

0.9999986*c

Explanation:

The ship would travel 2.54*10^7 light years, which means that at a speed close to the speed of light the trip would take 2.54*10^7 years from the point of view of an observer on Earth. However from the point of view of a passenger of that ship it will take only 70 years if the speed is close enough to the speed of light.

\Delta t = \Delta t' * \sqrt{1 - (\frac{v}{c})^2}

Where

Δt is the travel time as seen by a passenger

Δt' is the travel time as seen by someone on Earth

v is the speed of the ship

c is the speed of light in vacuum

We can replace the fraction v/c with x

\Delta t = \Delta t' * \sqrt{1 - x^2}

\sqrt{1 - x^2} = \frac{\Delta t}{\Delta t'}

1 - x^2 = (\frac{\Delta t}{\Delta t'})^2

x^2 = 1 - (\frac{\Delta t}{\Delta t'})^2

x = \sqrt{1 - (\frac{\Delta t}{\Delta t'})^2}

x = \sqrt{1 - (\frac{70}{2.54*10^7})^2} = 0.9999986

It would need to travel at 0.9999986*c

5 0
3 years ago
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