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Zina [86]
3 years ago
10

Which statements about cells are true? (Select all that apply)

Physics
1 answer:
Gemiola [76]3 years ago
7 0

Answer:

c human have eukaryotic cell

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All of the statements about nuclear reactions are true except All of the statements about nuclear reactions are true except ener
Lapatulllka [165]

A nuclear reaction will <u>not</u> be affected with the use of a catalyst.

8 0
3 years ago
the millersburg ferry (m=13000.0 kg loaded) puts its engines in full reverse and stops in 65 seconds. if the speed before brakin
kenny6666 [7]

The braking force is -400 N

Explanation:

We can solve this problem by using the impulse theorem, which states that the impulse applied on the ferry (the product of force and time) is equal to its change in momentum:

F \Delta t = m(v-u)

where in this problem, we have:

F is the force applied by the brakes

\Delta t = 65 s is the time interval

m = 13,000 kg is the mass of the ferry

u = 2.0 m/s is the initial velocity

v = 0 is the final velocity

And solving for F, we find the force applied by the brakes:

F=\frac{m(v-u)}{\Delta t}=\frac{(13000)(0-2.0)}{65}=-400 N

where the negative sign indicates that the direction is backward.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

4 0
3 years ago
By experiment, determine what makes a force attractive or repulsive. Describe your experiments and observations with some exampl
drek231 [11]

The charge present determines a force to be attractive or repulsive.

The charges acquired by two bodies determines the Force as Attractive Or Repulsive.

Electric Force applied due to Electrical charges is same in magnitude but opposite in direction. This corresponds this phenomenon equivalent to the Newton's Third Law.

Examples of the experiments and observations:

  • On combing hair through a comb and then keeping it close to small pieces of paper shows attraction of paper pieces towards the comb.

This occurs due to the Electric charges present in the comb that induces charge in paper pieces leading to their attraction.

  • In both Gravitational Force and Coulomb force, the force remains inversely proportional to the square of the distance following the Inverse Square Law being the Central Force system. This only differs by the fact that in Gravitational Force, masses are used and in Coulomb force, charges are used.

The more the distance between the charges, the less is the Electric Force.

The lesser the distance between the charges, the more is the Electric Force.

If both the objects are charged the same i.e. either positive or negative then the Force is Repulsive and if the charges are Oppositely charged then the force is attractive.

Hence, the charge present determines a force to be attractive or repulsive.

Learn more about Coulomb Force here, brainly.com/question/15451944

#SPJ4

6 0
2 years ago
A student is subjected to a reaction force of 10 N northward from a 5 kg block while pushing the block over a smooth, level sufa
harkovskaia [24]

Answer:

The Analysis Model approach we focus on in this revision lays out a standard set of situations that appear in most

physics problems. These situations are based on an entity in one of four simplification models: particle, system,

rigid object, and wave. Once the simplification model is identified, the student thinks about what the entity is

doing or how it interacts with its environment. This leads the student to identify a particular Analysis Model for the

problem. For example, if an object is falling, the object is recognized as a particle experiencing an acceleration due

to gravity that is constant. The student has learned that the Analysis Model of a particle under constant acceleration

describes this situation. Furthermore, this model has a small number of equations associated with it for use in starting problems, the kinematic equations presented in Chapter 2. Therefore, an understanding of the situation has led

to an Analysis Model, which then identifies a very small number of equations to start the problem, rather than the

myriad equations that students see in the text. In this way, the use of Analysis Models leads the student to identify

the fundamental principle. As the student gains more experience, he or she will lean less on the Analysis Model

approach and begin to identify fundamental principles directly.

To better integrate the Analysis Model approach for this edition, Analysis Model descriptive boxes have been

added at the end of any section that introduces a new Analysis Model. This feature recaps the Analysis Model introduced in the section and provides examples of the types of problems that a student could solve using the Analysis

Model. These boxes function as a “refresher” before students see the Analysis Models in use in the worked examples

for a given section.

Worked examples in the text that utilize Analysis Models are now designated with an AM icon for ease of reference. The solutions of these examples integrate the Analysis Model approach to problem solving. The approach is

further reinforced in the end-of-chapter summary under the heading Analysis Models for Problem Solving, and through

the new Analysis Model Tutorials that are based on selected end-of-chapter problems and appear in Enhanced

WebAssign.

Analysis Model Tutorials. John Jewett developed 16

Explanation:

5 0
3 years ago
A sample contains 20 kg of radioactive material. The decay constant of the material is 0.179 per second. If the amount of time t
Nataly [62]

Answer:

Explanation:

Given

N0 = 20kg (original substance)

decay constant λ = 0.179/sec

time t = 300s

We are to find N(t)

Using the formula;

n(t) = N0e^-λt

Substitute the given values

N(t) = 20e^-(0.179)(300)

N(t) = 20e^(-53.7)

N(t) = 20(4.7885)

N(t) =143.055

To know how much of the original material that is active, we will find N(t)/N0 = 143.055/20 = 7.152

About 7 times the original material is still radioactive

4 0
3 years ago
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