Answer:
The same pendulum could be adjusted to have the same period, in the equator must have a length of 3.949m.
Explanation:
Tnp= 4 sec
gnp= 9.83 m/sec²
Lnp= 3.97m
Tequ= 4 sec
gequ= 9.78 m/sec²
Lequ=?
Lequ= (Lnp* gequ) / gnp
Lequ= 3.949 m
Answer:
I = 0.0025 kg.m²
Explanation:
Given that
m= 2 kg
Diameter ,d= 0.1 m
Radius ,![R=\dfrac{d}{2}](https://tex.z-dn.net/?f=R%3D%5Cdfrac%7Bd%7D%7B2%7D)
![R=\dfrac{0.1}{2}](https://tex.z-dn.net/?f=R%3D%5Cdfrac%7B0.1%7D%7B2%7D)
R=0.05 m
The moment of inertia of the cylinder about it's axis same as the disc and it is given as
![I=\dfrac{mR^2}{2}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7BmR%5E2%7D%7B2%7D)
Now by putting the all values
![I=\dfrac{2\times 0.05^2}{2}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B2%5Ctimes%200.05%5E2%7D%7B2%7D)
I = 0.0025 kg.m²
Therefore we can say that the moment of inertia of the cylinder will be 0.0025 kg.m².
Answer:
average acceleration = 6 ![\frac{m}{s^2}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%5E2%7D)
Explanation:
Recall that the average acceleration
is defined by the change in velocity from an initial velocity
, to a final velocity
over the time (t) it took that change to happen. Then, in mathematical terms this is:
![a=\frac{v_f-v_i}{t}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv_f-v_i%7D%7Bt%7D)
with our information this becomes:
![a=\frac{v_f-v_i}{t} = \frac{100-40}{10}=6\,\frac{m}{s^2}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv_f-v_i%7D%7Bt%7D%20%3D%20%5Cfrac%7B100-40%7D%7B10%7D%3D6%5C%2C%5Cfrac%7Bm%7D%7Bs%5E2%7D)