what is the largest and smallest possible resultant force of two force with magnitude of 41N and 14N

A proton is accelerated down a uniform electric field of 450 N/C. Calculate the acceleration of this proton.

olasank [31]

Answer:

The acceleration of proton will be $431.137\times 10^8m/sec^2$

Explanation:

We have given electric field E = 450 N/C

Charge on proton $=1.6\times 10^{-19}C$

Force on electron due to electric field is given by $F=qE=1.6\times 10^{-19}\times 450=720\times 10^{-19}N$

Mass of electron $m=1.67\times 10^{-27}kg$

Now according to second law of motion $F=ma$

So $720\times10^{-19}=1.67\times 10^{-27}a$

$a=431.137\times 10^8m/sec^2$

So the acceleration of proton will be $431.137\times 10^8m/sec^2$

6 0

3 years ago

A bouncy ball is being thrown upwards with a velocity of 34 meters per second if you caught the ball at the same height you rele

Serga [27]

It took the ball 6.94 seconds to make the trip

Explanation:

A bouncy ball is being thrown upwards with a velocity of 34 meters per

second and you caught the ball at the same height you released it

1. The initial velocity of the ball is 34 m/s upward

2. The acceleration of gravity is -9.8 m/s²

3. You caught the ball at the same height you released it

We need to find how long it takes the ball to make the trip

You caught the ball at the same height you released it, then

→ The displacement of the trip s = zero meter

→ The ball thrown upward with initial velocity u = 34 m/s

→ The acceleration of gravity g = -9.8 m/s²

→ s = u t + $\frac{1}{2}$ g t²

Substitute the values of u , g , s in the rules

→ 0 = 34 t + $\frac{1}{2}$ (-9.8) t²

→ 0 = 34 t - 4.9 t²

Multiply both sides by -1

→ 4.9 t² - 34 t = 0

Take t as common factor

→ t(4.9 t - 34) = 0

Equate each factor by 0

→ t = 0 ⇒ initial position

→ 4.9 t - 34 = 0

Add 34 to both sides

→ 4.9 t = 34

Divide both sides by 4.9

→ t = 6.94 seconds ⇒ final position

It took the ball 6.94 seconds to make the trip

Learn more:

You can learn more about free fall in brainly.com/question/5531630

#LearnwithBrainly

5 0

3 years ago

Shadow is formed when an_____<br>object comes in the<br>way<br>of light.

Zanzabum

Answer:

shadow is formed when an opaque object comes on path of light shadows are formed because light travels in a straight line and it can't pass through an opaque object

7 0

3 years ago

Read 2 more answers

The aorta is approximately 25 mm in diameter. The mean pressure there is about 100 mmHg and the blood flows through the aorta at

Ksenya-84 [330]

Answer:

Explanation:

25 mm diameter

r₁ = 12.5 x 10⁻³ m radius.

cross sectional area = a₁

Pressure P₁ = 100 x 10⁻³ x 13.6 x 9.8 Pa

a )

velocity of blood v₁ = .6 m /s

Cross sectional area at blockade = 3/4 a₁

Velocity at blockade area = v₂

As liquid is in-compressible

a₁v₁ = a₂v₂

a₁ x .6 m /s = 3/4 a₁ v₂

v₂ = .8m/s

b )

Applying Bernauli's theorem formula

P₁ + 1/2 ρv₁² = P₂ + 1/2 ρv₂²

100 x 10⁻³ x 13.6 x10³x 9.8 + 1/2 X 1060 x .6² = P₂ + 1/2x 1060 x .8²

13328 +190.8 = P₂ + 339.2

P₂ = 13179.6 Pa

= 13179 / 13.6 x 10³ x 9.8 m of Hg

P₂ = .09888 m of Hg

98.88 mm of Hg

8 0

3 years ago

C. is what percent of 125?

solmaris [256]

Answer:

Step 1: We make the assumption that 125 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=125$.

Step 4: In the same vein, $x\%=125$.

Step 5: This gives us a pair of simple equations:

$100\%=125(1)$.

Explanation:

4 0

3 years ago

what is the largest and smallest possible resultant force of two force with magnitude of 41N and 14N​

what is the largest and smallest possible resultant force of two force with magnitude of 41N and 14N