Answer:
magnitude m = 5440.26 M
average speed is = 25.05 m/s
average velocity = 14.62 m/s
Explanation:
given data
speed v1 = 24 m/s
time t1 = 3 min = 180 s
speed v2 = 25 m/s
time t2 = 2.2 min = 132 s
speed v3 = 30 m/s
time t3 = 1 min = 60 s
total time = 6.2 min = 372 s
to find out
displacement in m and average speed and average velocity
solution
so we find here displacement
displacement = vt .............1
so
displacement 1 = 24 × 180 = 4220 m south = -4220 j ..........2
displacement 2 = 25 × 132 = 3300 m west = -3300 i ...........3
distance 3 = 30 × 60 = 1800 m
displacement = 1800 cos45 -i + 1800 cos45 j
displacement = -1272.79 i + 1272.79 j .............4
so total displacement D = equation 2 + equation 3 + equation 4
total displacement D = -4220 j -3300 i -1272.79 i + 1272.79 j
total displacement D = -2947.21 j - 4572.79 i
so magnitude m = √(-2947.21)² + (-4572.79)² )
so magnitude m = 5440.26 M
and
average speed is = total distance / time
average speed is = (4220 + 3300+ 1800 ) / 372
average speed is = 25.05 m/s
and
average velocity = total displacement / time
average velocity = 5440.26 / 372
average velocity = 14.62 m/s
