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netineya [11]
1 year ago
15

What happens to the particles that make up a gas when it is cooled?

Physics
1 answer:
hoa [83]1 year ago
5 0

When the particles are cooled, the  particles condense.

<h3>What happens when a gas is cooled?</h3>

We know that the temperature is defined as the average kinetic energy of the molecules of a gas. Given that we have gases that are at a particular temperature, the average kinetic energy of the gas is in sync with the temperature of the gas.

As we cool the gas, the average kinetic energy of the gas molecules would reduce and the gases move more slowly thus they are able to come closer together. This process is called condensation of the gas.

Learn more about temperature:brainly.com/question/15354399

#SPJ1

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Which of the following has zero acceleration? an object...
tangare [24]

Answer:

B object at rest

Explanation:

object at rest means it wouldn't be moving, like a parked car or sleeping person therefore, B is the correct answer

8 0
3 years ago
Two resistances of 100ohms and 0 ohms were connected in parallel. What is the overall resistance
Inga [223]

Answer:

20 ohms,100*2/10=20

Explanation:

since it as to be in parallel arrangement and connected in side by side due to same p.d in a cross each resistor

6 0
3 years ago
HELP I'll Mark as brainliest!
Alex777 [14]

Answer: Gus sues Russell for stealing postage stamps

Explanation:

3 0
3 years ago
Consider horizontal parallel plates with a fixed potential difference. The upper plate has a voltage difference of 30 V with the
BlackZzzverrR [31]

relation between potential difference and electric field is given as

E . d = \Delta V

so here we know that

d = 3 cm

\Delta V = 30 V

E \times 0.03 = 30

E = 1000 N/C

So now when plates are separated to 4 cm distance carefully

the potential difference between them will change but the electric field between them will remain constant

So at distance of 4 cm also the electric field will be E = 1000 N/C

5 0
3 years ago
A certain unfiltered full-wave rectifier with 120 V, 60 Hz input produces an output with a peak of 15 V. When a capacitor-input
KATRIN_1 [288]

Answer:

The peak-to-peak ripple voltage = 2V

Explanation:

120V and 60 Hz is the input of an unfiltered full-wave rectifier

Peak value of  output voltage = 15V

load connected = 1.0kV

dc output voltage = 14V

dc value of the output voltage of capacitor-input filter

where

V(dc value of output voltage) represent V₀

V(peak value of output voltage) represent V₁

V₀ = 1 - ( \frac{1}{2fRC})V₁

make C the subject of formula

V₀/V₁ = 1 - (1 / 2fRC)

1 / 2fRC = 1 - (v₀/V₁)

C = 2fR ((1 - (v₀/V₁))⁻¹

Substitute  for,

f = 240Hz , R = 1.0Ω, V₀ = 14V , V₁ = 15V

C = 2 * 240 * 1 (( 1 - (14/15))⁻¹

C = 62.2μf

The peak-to-peak ripple voltage

= (1 / fRC)V₁

= 1 /  ( (120 * 1 * 62.2) )15V

= 2V

The peak-to-peak ripple voltage = 2V

3 0
4 years ago
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