Answer:

Explanation:
Given that,
The mass of the Jupiter,
The radius of Jupiter,
We need to find the acceleration due to gravity on Jupiter. The formula is

Put all the values,

So, the value of acceleration due to gravity on the Jupiter is
.
Answer:
Explanation:
We shall apply Doppler's effect here .
original frequency = 79.79 kHz
apparent frequency due to movement of source ( bat ) = 81.63 Hz
Let the velocity of bat be v .
expression for apparent frequency can be given as follows
n = 
n is apparent frequency , n₀ is original frequency , V is velocity of light and v is velocity of source of sound
Putting the values
81.63 = 
340-v = 332.33
v = 7.67 m /s
velocity of bat is 7.67 m /s .
They are magnetic
Your welcome;)