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GuDViN [60]
3 years ago
14

Please answer in your own words and I will mark brainlist, Compare all matters from the view of passing light through them (name

3 types and write if they pass the light or not.)​
Physics
1 answer:
prisoha [69]3 years ago
4 0

Answer:

Light passes through the gas

Light passes through the pure water

Light passes through some solids

Explanation:

In gasses, there are many spaces between the molecules. These spaces allow light to pass through them without any interruption.

In pure water, there are some spaces between particles. these particles allow some light rays to pass theough, some to move through the common boundary and reflec5 some of them.

in solids, some allow light to pass through as they are transparent or translucent

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For Part A, Sebastian decided to use the copper cylinder. How would the magnitude of his q and ∆H compare if he were to redo Par
Vitek1552 [10]

The magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

The given parameters;

  • <em>initial temperature of metals, =  </em>T_m<em />
  • <em>initial temperature of water, = </em>T_i<em> </em>
  • <em>specific heat capacity of copper, </em>C_p<em> = 0.385 J/g.K</em>
  • <em>specific heat capacity of aluminum, </em>C_A = 0.9 J/g.K
  • <em>both metals have equal mass = m</em>

The quantity of heat transferred by each metal is calculated as follows;

Q = mcΔt

<em>For</em><em> copper metal</em><em>, the quantity of heat transferred is calculated as</em>;

Q_p = (m_wc_w + m_pc_p)(T_m - T_i)\\\\Q_p = (T_m - T_i)(m_wc_w ) + (T_m - T_i)(m_pc_p)\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m_p(T_m - T_i)\\\\m_p = m\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m(T_m - T_i)\\\\let \ (T_m - T_i)(m_wc_w )  = Q_i, \ \ \ and \ let \ (T_m- T_i) = \Delta t\\\\Q_p = Q_i + 0.385m\Delta t

<em>The </em><em>change</em><em> in </em><em>heat </em><em>energy for </em><em>copper metal</em>;

\Delta H = Q_p - Q_i\\\\\Delta H = (Q_i + 0.385m \Delta t) - Q_i\\\\\Delta H = 0.385 m \Delta t

<em>For </em><em>aluminum metal</em><em>, the quantity of heat transferred is calculated as</em>;

Q_A = (m_wc_w + m_Ac_A)(T_m - T_i)\\\\Q_A = (T_m -T_i)(m_wc_w) + (T_m -T_i) (m_Ac_A)\\\\let \ (T_m -T_i)(m_wc_w)  = Q_i, \ and \ let (T_m - T_i) = \Delta t\\\\Q_A = Q_i \ + \ m_Ac_A\Delta t\\\\m_A = m\\\\Q_A = Q_i \ + \ 0.9m\Delta t

<em>The </em><em>change</em><em> in </em><em>heat </em><em>energy for </em><em>aluminum metal </em><em>;</em>

\Delta H = Q_A - Q_i\\\\\Delta H = (Q_i + 0.9m\Delta t) - Q_i\\\\\Delta H = 0.9m\Delta t

Thus, we can conclude that the magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

Learn more here:brainly.com/question/15345295

6 0
2 years ago
Which nucleus completes the following equation?<br> 212 86 Rn-&gt; 4 2 He+?
Inessa [10]

Answer:

A

Explanation:

208+4=212

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The correct answer is A

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1 year ago
How does a force fields work how do you make your own force field
Irina18 [472]
A force field works the same as a shield. I protects what ever is inside, or behind the field.
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3 years ago
Timmy bikes to school 3 kilometers east and 2 kilometers south. What is Timmy's final displacement?
vovikov84 [41]

Answer:

3.6km South East

Explanation:

Displacement is the shortest distance between the starting point and the ending point and the direction it is displaced in. To calculate the displacement we can use the pythagoras theorem because the 3km East and the 2km south form the two shorter sides of a right angled triangle between the starting and ending points. So, the displacement is the length C of the triangle which we can calculate as follows:

Pythagoras Theorem:

a^2+b^2=c^2

(2)^2+(3)^2=c^(2)

4+9=c^2

Square root 13 = c

c=3.6km (1dp)

The total displacement is 3.6km and is in the approximate direction of South East (because he travelled east and south).

Hope this helped!

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3 years ago
Which moves more: the air molecules or the energy of the sound?
MatroZZZ [7]

Answer:

A sound wave can be affected by a lot of different variables. As an audio engineer some of the more common things we deal with involve air temperature, humidity and even wind. The first two affect the speed at which the wave travels, while wind can actually cause a phase like effect if it is blowing hard enough. Another big one though not directly related to the air is walls and other solid objects that cause the sound wave to bounce off of them and reflect. This causes a secondary wave that isn’t as strong as the first wave but is the cause of “muddy” sounding venues when you are indoors.

Explanation:

7 0
2 years ago
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