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3 years ago

How does Sonar work?i will mark brainliest pls help

1 answer:

5 0

I don't like the wording of any of the choices on the list.

SONAR generates a short pulse of sound, like a 'peep' or a 'ping',
focused in one direction. If there's a solid object in that direction,
then some of the sound that hits it gets reflected back, toward the
source. The source listens to hear if any of the sound that it sent
out returns to it. If it hears its own 'ping' come back, it measures
the time it took for the sound to go out and come back. That tells
the SONAR equipment that there IS a solid object in that direction,
and also HOW FAR away it is.

RADAR works exactly the same way, except RADAR uses radio waves.

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X-ray photons of wavelength 0.02480 nm are incident on a target and the Compton scattered photons are observed at 90 degrees.

Rashid [163]

Answer:

Explanation:

(a) This problem can be solved by using the formula for Compton effect

$\lambda_{a}-\lambda_{b}=\frac{h}{m_{o}c}(1-cos\phi)$

where h is the planck constant, Φ is the angle of the scattered photon, m is the mass of the particle (in this case we take an electron) and c is the speed of ligth.

By taking the wavelength of the scattered photon and by replacing we have

$\lambda_{a}=\frac{6.62*10^{-34}m^{2}\frac{kg}{s}}{(9.1*10^{-31}kg)(3*10^{8}\frac{m}{s})}+0.02480*10^{-9}m=2.72*10^{-11}m=0.0272nm$

(b)

$p=\frac{h}{\lambda_{b}}=\frac{6.62*10^{-34}m^{2}\frac{kg}{s}}{0.0248*10^{-9}m}=2.66*10^{-23}kg\frac{m}{s}$

(c)

The energy is conserved, hence we have

$E_{i-photon}=E_{k-electron}+E_{s-photon}$

that is, the sum of the kinetic energy of the scattered electron and the energy of the scattered photon is equal to the energy of the incident photon. By taking Ek we have

$E_{k-e}=E_{i-p}-E_{s-p}=h\frac{c}{\lambda_{b}}-h\frac{c}{\lambda_{a}}\\\\E_{k-e}=(6.62*10^{-34}m^{2}\frac{kg}{s})(3*10^{8}\frac{m}{s})(\frac{1}{0.0248*10^{-9}m}-\frac{1}{0.0272*10^{-9}m})\\\\E_{k-e}=7.06*10^{-16}J=7.06*10^{-16}(6.242*10^{18}eV)=4.4keV$

(d)

$E_{k-e}=\frac{m_{e}v^{2}}{2}\\\\v=\sqrt{\frac{2E_{k-e}}{m_{e}}}=3.9*10^{7}\frac{m}{s}\\\\p_{e}=m_{e}*v=3.5*10^{-23}kg\frac{m}{s}$

I hope this is useful for you

regards

8 0

3 years ago

in a paragraph explain how electncity is generated at a power plant. please don't answer if you don't know

Anna [14]

Answer:

A turbine spins to generate electricity. There are many ways to spin the turbine by using water, steam, nuclear and so on.

3 0

3 years ago

While wearing rubber-soled shoes, you rub a helium balloon on your sweater. the balloon becomes negative charged. now release th

Alex17521 [72]

You are effectively creating static electricity.

8 0

3 years ago

The uncertainty Δp sets a lower bound on the average momentum of a particle in the nucleus. If a particle's average momentum wer

kirill [66]

Answer: The minimum kinetic energy Kmin is 1.3 × 10^-13 J

Explanation: Please see the attachments below

8 0

3 years ago

What product is obtained from the aldol condensation of cyclohexanone?

Evgesh-ka [11]

Answer:

First product is FCH-OH chemically known as 2-[2-furyl(hydroxyl)methyl]-Second product is FCH i.e (2E)-2-[2-furyl-methylene]-cyclohexanone

Explanation:

Please see the attached image for complete chemical reaction of aldol condensation of cyclohexanone

Aldol Condensation is a form of electrophilic substitution reaction in which the alpha carbon in enols or enolate anions is substituted by an electrophile to form carbon-carbon bond. Cyclohexanone also known as the first ketone consists of two alpha-carbons and four potential substitutions i.e alpha-hydrogens but none of the hydrogen on the ring is substituted. Ketones such as cyclohexanone are much more acidic than their parent hydrocarbon.

First product is FCH-OH chemically known as 2-[2-furyl(hydroxyl)methyl]-cyclohexanone that further undergoes dehydration resulting into FCH i.e (2E)-2-[2-furyl-methylene]-cyclohexanone

Based on the explanations above, the compound formed is shown in the image.

6 0

2 years ago