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NISA [10]
3 years ago
6

How does Sonar work?i will mark brainliest pls help

Physics
1 answer:
Fittoniya [83]3 years ago
5 0
I don't like the wording of any of the choices on the list.

SONAR generates a short pulse of sound, like a 'peep' or a 'ping',
focused in one direction.  If there's a solid object in that direction,
then some of the sound that hits it gets reflected back, toward the
source.  The source listens to hear if any of the sound that it sent
out returns to it.  If it hears its own 'ping' come back, it measures
the time it took for the sound to go out and come back.  That tells
the SONAR equipment that there IS a solid object in that direction,
and also HOW FAR away it is.

RADAR works exactly the same way, except RADAR uses radio waves. 


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As per Newton's III law

Every action force that is applied on an object must be equal and opposite to reaction force applied by that object.

It can be said that when we apply any force on an object then this applied force is known as action force and at the same time that object also apply an opposite direction force on us which is known as reaction force having same magnitude.

So as per above theory

Action Force = Reaction Force (magnitude)

while both forces are always opposite in direction

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Carl knows that water moves through different kinds of soil at different rates. How easily water moves through a soil is known a
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c    The amount of water that goes in each pot

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Anya has 115 mangoes lauren has five times the the number of mangoes Anya has they put them together and sold them in the market
inessss [21]

$10,350 is the amount of money that has been collected mangoes are sold by Anya and Lauren at $15.

Number of mangoes of Anya's = 115 mangoes

Number of mangoes of Lauren's = 5 × 115 = 575 mangoes

Total number of mangoes = Number of mangoes Anya has + Number of mangoes Lauren has

= 115 + 575

= 690 mangoes

Amount each mango sold = $15

The total amount of money collected = Total number of mangoes × Amount each mango were sold

= 690 × 15

= $10,350

So, therefore, Anya and Lauren sold their total mangoes for $10,350.

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5 0
1 year ago
spaceship of mass m travels from the Earth to the Moon along a line that passes through the center of the Earth and the center o
satela [25.4K]

Answer:

the correct result is r = 3.71 10⁸ m

Explanation:

For this exercise we will use the law of universal gravitation

          F = - \frac{m_{1} m_{2} }{r^2}

We call the masses of the Earth M, the masses of the moon m and the masses of the rocket m ', let's set a reference system in the center of the Earth, the distance from the Earth to the moon is d = 3.84 108 m

rocket force -Earth

          F₁ = - \frac{m' M }{r^2}

rocket force - Moon

          F₂ = - \frac{m' m }{(d-r)^2}

in the problem ask for what point the force has the relation

          2 F₁ = F₂

let's substitute

          2 2 \frac{M}{r^2} = \frac{m}{(d-r)^2}

          (d-r) ² = \frac{m}{2M} r²

           d² - 2rd + r² = \frac{m}{2M} r²

           r² (1 -\frac{m}{2M}) - 2rd + d² = 0

Let's solve this quadratic equation to find the distance r, let's call

           a = 1 - \frac{m}{2M}

           a = 1 - \frac{7.36 10^{22} }{2 \  5398 10^{24}} = 1 - 6.15 10⁻³

           a = 0.99385

         

            a r² - 2d r + d² = 0

           r =  \frac  {2d \frac{+}{-}   \sqrt{4d^2 - 4 a d^2}} {2a}

           r = [2d ± 2d \sqrt{1-a}] / 2a

           r = \frac{d}{a}   (1 ± √ (1.65 10⁻³)) =  \frac{d}{a} (1 ± 0.04)

           r₁ = \frac{d}{a} 1.04

           r₂ = \frac{d}{a} 0.96

let's calculate

           r₁ = \frac{3.84 10^8}{0.99385} 1.04

           r₁ = 401.8 10⁸ m

          r₂ = \frac{3.84 10^8}{0.99385} 0.96

          r₂ = 3.71 10⁸ m

therefore the correct result is r = 3.71 10⁸ m

3 0
3 years ago
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