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ad-work [718]
3 years ago
6

A weightlifter lifts a 250-kg mass 0.5 meters above his head, how much PEg does the mass have (Note: g=9.8 m/s2)? Round your ans

wer to the nearest whole number. J
Physics
2 answers:
morpeh [17]3 years ago
6 0

Answer:

1225 J

Explanation:

The Gravitational potential energy (PEG) gained by a mass lifted above the ground is given by

PE=mgh

where

m is the mass

g = 9.8 m/s^2 is the acceleration due to gravity

h is the height at which the object has been lifted

In this problem, we have

m = 250 kg

h = 0.5 m

So, the PE of the object is

PE=(250 kg)(9.8 m/s^2)(0.5 m)=1225 J

disa [49]3 years ago
4 0

Answer:

1225J

Explanation:

The Gravitational potential energy (PEG) gained by a mass lifted above the ground is given by

where

m is the mass

g = 9.8 m/s^2 is the acceleration due to gravity

h is the height at which the object has been lifted

In this problem, we have

m = 250 kg

h = 0.5 m

So, the PE of the object is

1225J

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Explanation:

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3 years ago
At resonance, what is impedance of a series RLC circuit? less than R It depends on many other considerations, such as the values
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Answer:

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Explanation:

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3 years ago
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Natasha2012 [34]

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Explanation:

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r_{a} is the apoapsis (the longest distance between the moon and its planet)

r_{p}=0.27 r_{a} is the periapsis (the shortest distance between the moon and its planet)

Then:

e=\frac{r_{a}-0.27 r_{a}}{r_{a}+0.27 r_{a}}

e=\frac{0.73 r_{a}}{1.27 r_{a}}

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If two monochromatic light waves undergo destructive interference, the amplitude of the resultant wave is
lesya692 [45]

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Then if two light waves undergo destructive interference, the amplitude of the resultant wave in that particular point is 0.

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3 years ago
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For an object in uniform circular motion, what can you say about the directions of the velocity, acceleration, and net force vec
zavuch27 [327]

Answer: b) The velocity vector is perpendicular to the acceleration vector; the acceleration vector is parallel to the net force vector.

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