A steel ball of mass 0.1 kg falls from a height of 1.8metres

Blue bumper car, traveling east with a force of 100 N, runs into a yellow bumper car traveling west with a force of 300 N. Becau

Pani-rosa [81]

Answer:

the blue bumper car

Explanation:

because the yellow bumper car is coming in with much more force

and according to Newton, actions and reactions are equal and opposite, so the yellow bumper car will five out 300N while the blue car will give out only 100N

then it almost because a fight between 300N vs 100N

and obviously, the 300N will win and the 100N will be pushed back

4 0

3 years ago

Which observation did researchers make in studies on separated twins ?

choli [55]

Depending on whether they where conjoined initially, or where born separately really changes the answer of this question. Although studies show that twins generally have a kinetic link, more practical research says that twins are 25% more likely to both be left handed, which is a recessive gene, they are also more likely to die in child birth, twins are more likely to understand and be biligual, along with many other advantages twins may have.

7 0

3 years ago

How far (in feet) could a pitcher throw a baseball on flat, level ground if he can throw it at 100mph? (Neglect wind drag and th

ehidna [41]

Answer:

R = 668.19 ft

Explanation:

given,

speed of the ball thrown by the pitcher = 100 mph

to travel maximum distance θ = 45°

distance traveled by the ball = ?

using formula

1 mph = 0.44704 m/s

100 mph = 44.704 m/s

$R = \dfrac{u^2sin2\theta}{g}$

$R = \dfrac{44.704^2sin2\times 45}{9.81}$

R = 203.71 m

1 m = 3.28 ft

R = 203.71 × 3.28

R = 668.19 ft

hence, ball will go at a distance of 668.19 ft when pitcher throw it at 100 mph.

6 0

3 years ago

In March 2006, two small satellites were discovered orbiting Pluto, one at a distance of 48,000 km and the other at 64,000 km. P

Natasha_Volkova [10]

Answer

given,

distance of first satellite = 48,000 Km

distance of second satellite = 64,000 Km

orbital period = 6.39 day

Using equation of time period

$T = \dfrac{2\pi r^{3/2}}{\sqrt{Gm_{pluto}}}$

now, from the above equation we can say that only variable is Time period and r is the radii of orbit.

from the first satellite

$\dfrac{T_{charon}}{r^{3/2}_{charon}}=\dfrac{T_{sat1}}{r^{3/2}_{sat1}}$

$T_{sat1}=\dfrac{T_{charon}\ r^{3/2}}{r^{3/2}_{charon}}$

$T_{sat1}=\dfrac{6.39\times (48000)^{3/2}}{19600^{3/2}}$

$T_{sat1}=24.5\ days$

for second satellite

$T_{sat2}=\dfrac{T_{charon}\ r^{3/2}_{sat2}}{r^{3/2}_{charon}}$

$T_{sat1}=\dfrac{6.39\times (64000)^{3/2}}{19600^{3/2}}$

$T_{sat1}=37.7\ days$

7 0

3 years ago

I need help in my physics class and show me how it’s done

Korolek [52]

If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

$A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)$

Where | A | is the magnitude of the vector and $\alpha$ is the angle that it forms with the x axis in the opposite direction to the hands of the clock.