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pickupchik [31]
3 years ago
9

A steel ball of mass 0.1 kg falls from a height of 1.8metres

Physics
1 answer:
murzikaleks [220]3 years ago
8 0
And what about it?????????
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Saved
Anon25 [30]

Total distance moved by bead is 1.952 cm.

Explanation:

Let first consider all data that are given in question.

1.    F = 8 N                       ...force acting on string

2.   f  = 2 Hz                     ...frequency of system

3.   β = 4 cm = 0.04 m    ...wavelength of wave formed due to vibration           4.   A =  1 cm  = 0.01 m     ...Amplitude of vibration

Under certain conditions, waves can bounce back and forth through a particular region, effectively becoming stationary. These are called standing waves.

Here,it is due to vibration induced in spring due to tension induced in string

Standing wave equation is given by

y = (x,t) = 2A * sinK x * cos (wt)                ...(1)

Let first find, value of K, x, w, t

k = 2 * pi / beta                                          ....(2)

Where β is wavelength in meters

                   K is wave number

k = 2 * pi / 0.01

k = 628.31 m^{-1}

now, let us find value of w

W = 2 x pi x f                               ....(3)

                where f is frequency in hertz

W = 2 x pi x 2

W = 4 x pi

W = 0.08 \frac{m}{s}

y = (x,t) = 2A * sinK x * cos (wt)

now, let us find value of v that is wave speed

Notice that some x-positions of the resultant wave are always zero no matter what the phase relationship is.  These positions are called nodes.

Finding the positions where the sine function equals zero provides the positions of the nodes.

In our case, and      

K * x = pi

x = 0.04 / 2

x = 0.02

y = (0.02,1) = 2(0.01) * sin pi  * cos (12.5664 * 1)

y = (0.02,1) = 2(0.01) * -1  * cos 0.9761

Y = 1.952 cm

Finally, when bead is at middle of the string, total distance after stretch covered  is 1.952 cm.

3 0
3 years ago
A car traveling 34 mi/h accelerates uniformly for 4 s, covering 615 ft in this time. What was its acceleration? Round your answe
Contact [7]

Answer:

51.94 ft/s²

257.63 ft/s

Explanation:

t = Time taken = 4 s

u = Initial velocity = 34 mi/h

v = Final velocity

s = Displacement = 615 ft

a = Acceleration

Converting velocity to ft/s

34\ mi/h=\frac{34\times 5280}{3600}=49.87\ ft/s

Equation of motion

s=ut+\frac{1}{2}at^2\\\Rightarrow a=2\frac{s-ut}{t^2}\\\Rightarrow a=2\left(\frac{615-49.87\times 4}{4^2}\right)\\\Rightarrow a=51.94\ ft/s^2

Acceleration is 51.94 ft/s²

v=u+at\\\Rightarrow v=49.87+51.94\times 4\\\Rightarrow v=257.63\ ft/s

Final velocity at this time is 257.63 ft/s

5 0
3 years ago
Elements in Group VIIIA (also known as Group 18, or the noble gases) have
Sonbull [250]
The answer is C (the same number of valence electrons)
3 0
2 years ago
If the mass of the object is doubled and the speed is halved then kinetic energy will change by a factor of:
Orlov [11]
I could be wrong but I believe it’s 1/2
6 0
3 years ago
Which of the following is not the result of nuclear decay.
svlad2 [7]

Answer:it’s c

Explanation:

7 0
3 years ago
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