Answer:
ΔT = 78.32 °C
Explanation:
Kinetic energy of bullet is K
K = mv²/2
= .004 * ( 200 m/s )²/2
= 80 J
Half of the heat E = 40 J
Now a per the equation of energy transferred ,
E = cm ΔT
c is the specific heat of latent, m is the mass and ΔT is the change in temperature.
ΔT = 40 / ( .0305 × 4186 × .004)
ΔT = 78.32 °C
Displacement from the center line for minimum intensity is 1.35 mm , width of the slit is 0.75 so Wavelength of the light is 506.25.
<h3>How to find Wavelength of the light?</h3>
When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.
This is a straightforward situation in which we can apply the
Fraunhofer single slit diffraction equation:
y = mλD/a
Where:
y = Displacement from the center line for minimum intensity = 1.35 mm
λ = wavelength of the light.
D = distance
a = width of the slit = 0.75
m = order number = 1
Solving for λ
λ = y + a/ mD
Changing the information that the issue has provided:
λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2
=5.0625 *10^-7 = 506.25
so
Wavelength of the light 506.25.
To learn more about Wavelength of the light refer to:
brainly.com/question/15413360
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The electromagnetic spectrum is made up of waves of different lengths, forming bands.
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