All categories

3 years ago

Where is earwax located and produced in your ear? Why is it important

2 answers:

6 0

The earwax is located in the ear canal. Earwax is important because it moisturizes the skin of ear, preventing dry itchy ears. It also contaisn special chemicals that fight of ear infections.
~Deceptiøn

Bogdan [553]3 years ago

5 0

Answer:

It is located in Ear Canal and produced by dead skin cells and hairs.

Explanation:

Ear-wax or "Cerumen" in medical terminology is red, grey, yellow and orange.

"Cerumen" or Ear-Wax located in the human and mammals ear canal,

Ear-Wax produced in the third outer portion of the Ear. it is a mixture of secretions mainly it consists of dead skin cells and hairs.

It protects the skin of the Ear during cleaning and oiling of Ear, it further protects the ear from fungus, Insects, and Bacteria.

Excess of Ear-Wax causes blockage in the Ear canal and hearing loss.

You might be interested in

In terms of entropy and energy, systems in nature tend to undergo changes toward

andrew-mc [135]

Number 2 lower entropy and higher entropy

7 0

3 years ago

If 550 mL of a 3.50 M KCl solution are set aside and alowed to evaporate unti the

andrezito [222]

1) list givens and convert if necessary

C₁ = 3.50 mol/L

V₁ = 0.550 L

C₂ = ?

V₂ = 0.275 L

2) rearrange formula

$C_{1}V_{1}=C_{2}V_{2}\\\\C_{2}=\frac{C_{1}V_{1}}{V_{2}}$

3) solve

$C_{2}=\frac{(3.50\ mol/L)(0.550\ L)}{(0.275\ L)}$

C₂ = 7.00 mol/L

5 0

3 years ago

Complete this sentence: The total mass of the products in any chemical reaction is equal to

Komok [63]

Answer:

This law states that, despite chemical reactions or physical transformations, mass is conserved — that is, it cannot be created or destroyed — within an isolated system. In other words, in a chemical reaction, the mass of the products will always be equal to the mass of the reactants.

Explanation:

5 0

3 years ago

Read 2 more answers

Coal gasification is a multistep process to convert coal into cleaner-burning fuels. In one step, a coal sample reacts with supe

ddd [48]

Answer :

The enthalpy of reaction is, -187.6 kJ/mol

The total heat will be, -2251 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

(a) The formation of $CH_4$ will be,

$2C(coal)+2H_2O(g)\rightarrow CH_4(g)+CO_2(g)$ $\Delta H_{rxn}=?$

The intermediate balanced chemical reaction will be,

(1) $C(coal)+H_2O(g)\rightarrow CO(g)+H_2(g)$ $\Delta H_1=29.7kJ$

(2) $CO(g)+H_2O(g)\rightarrow CO_2(g)+H_2(g)$ $\Delta H_2=-41kJ$

(3) $CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)$ $\Delta H_3=-206kJ$

We are multiplying equation 1 by 2 and then adding all the equations, we get :

(b) The expression for enthalpy of reaction will be,

$\Delta H_{rxn}=2\times \Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H_{rxn}=(2\times 29.7)+(-41)+(-206)$

$\Delta H_{rxn}=-187.6kJ/mol$

Therefore, the enthalpy of reaction is, -187.6 kJ/mol

(c) Now we have to calculate the total heat.

$\Delta H=\frac{q}{n}$

or,

$q=\Delta H\times n$

where,

$\Delta H$ = enthalpy change = -187.6 kJ/mol

q = heat = ?

n = number of moles of coal = $\frac{1.00\times 1000g}{12.00g/mol}=83.33mol$

Now put all the given values in the above formula, we get:

$q=(-187.6kJ/mol)\times (83.33mol)=-2.251kJ$

Thus, the total heat will be, -2251 kJ

4 0

4 years ago

What are two properties of liquids, solids, gases and matter. What are two important things about them.

larisa86 [58]

Solids— have tightly packed molecules, structured shape

Liquid— have no definite shape and the molecules are not tightly packed like a solid, they are a lot more loose.

Gas— No structure at all, molecules are free flowing

Sorry I couldn’t be a better help.. but I hope this gives you a bit of an idea :)

4 0

4 years ago