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kirza4 [7]
3 years ago
13

5. A box with a volume of 22.4 L contains 1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C. Which of the following statements

is true?
A. The total pressure is 202 kPa.

B. The partial pressure of N2 is 101 kPa.

C. The total pressure in the box is 101 kPa.

D. The partial pressures of N2 and H2 are equal.
Chemistry
1 answer:
love history [14]3 years ago
7 0

B. The partial pressure of N2 is 101 kPa

<h3>Further explanation</h3>

Given

volume = 22.4 L

1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C

Required

Total pressure and partial pressure

Solution

Ideal gas law :

PV = nRT

n total = 3 mol

T = O °C + 273 = 273 K

P = nRT/V

P = 3 x 0.08205 x 273 / 22.4

P total = 3 atm = 303,975 kPa

P Nitrogen = 1/3 x 303.975 = 101.325 kPa

P Hydrogen = 2/3 x 303.975 = 202.65 kPa

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The system will adjust itself in order to resist the change.

Explanation:

  • Frenchman Le Chatelier in 1888 is credited with the Le Chatelier's principle
  • His principle is a summary drawn from his findings on various factors that affects equilibrium.
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Chemical equilibrium brainly.com/question/10838453

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7 0
3 years ago
The overall cell reaction occurring in an alkaline battery isZn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s) (b) If 4.50 g of zin
Airida [17]

5.911 grams of manganese dioxide and 1.224 gram of water are consumed.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

The given reaction balanced equation is:

Zn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s)

<h3>How to find the number of moles ?</h3>

To find the number of moles use the expression:

Number of moles = \frac{\text{Given mass}}{\text{Molar mass}}

Here,

Mass of Zn = 4.50 g

Molar mass of Zn = 65.4 g/mol

Now put the value in above expression

Number of moles of Zn = \frac{\text{Given mass}}{\text{Molar mass}}

                                       = \frac{4.5\ g}{65.4\ \text{g/mol}}

                                       = 0.068 mol

Mass of MnO₂ = Moles of MnO₂ × Molar mass of MnO₂

                        = 0.068 mol × 86.9368 g/mol

                         = 5.911 g

Mass of H₂O = Moles of H₂O × Molar mass of H₂O

                     = 0.068 mol × 18.0 g/mol

                     = 1.224 g

Thus from the above conclusion we can say that 5.911 grams of manganese dioxide and 1.224 gram of water are consumed.

                 

Learn more about the Balanced chemical equation here: brainly.com/question/26694427

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