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kirza4 [7]
3 years ago
13

5. A box with a volume of 22.4 L contains 1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C. Which of the following statements

is true?
A. The total pressure is 202 kPa.

B. The partial pressure of N2 is 101 kPa.

C. The total pressure in the box is 101 kPa.

D. The partial pressures of N2 and H2 are equal.
Chemistry
1 answer:
love history [14]3 years ago
7 0

B. The partial pressure of N2 is 101 kPa

<h3>Further explanation</h3>

Given

volume = 22.4 L

1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C

Required

Total pressure and partial pressure

Solution

Ideal gas law :

PV = nRT

n total = 3 mol

T = O °C + 273 = 273 K

P = nRT/V

P = 3 x 0.08205 x 273 / 22.4

P total = 3 atm = 303,975 kPa

P Nitrogen = 1/3 x 303.975 = 101.325 kPa

P Hydrogen = 2/3 x 303.975 = 202.65 kPa

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Salt water contains n sodium ions (NA ) per cubic meter and n chloride ions (Cl-) per cubic meter. A battery is connected to met
IRINA_888 [86]

Answer: hello your question is incomplete below is the complete question

Salt water contains n sodium ions (Na+) per cubic meter and n chloride ions (Cl−) per cubic meter. A battery is connected to metal rods that dip into a narrow pipe full of salt water. The cross sectional area of the pipe is A. The magnitude of the drift velocity of the sodium ions is VNa​ and the magnitude of the drift velocity of the chloride ions is VCl​.

What is the magnitude of the ammeter reading ?

answer :

| I | = neAVₙₐ  + neAV (Cl-)

Explanation:

Given that there are N sodium ions

<u>Determine the Magnitude of the ammeter reading </u>

| I | = current due to sodium ions + current due to (Cl-) ions

     = neAVₙₐ  + neAV (Cl-)

3 0
3 years ago
A pipe leaks water at a rate of 1.24 mL/s. What is the rate of the water leak in L/hr?
Umnica [9.8K]

Answer:

b)4.46 L/hr

Explanation:

To solve this question we need to convert the mL to liters (Using the conversion of 1000mL = 1L) and convert the time from seconds to hours (3600s = 1hr)

<em>mL to L:</em>

1.24mL/s * (1L / 1000mL) = 0.00124L/s

<em>seconds to hours:</em>

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3 0
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Jim brings his finger near a metal doorknob and receives a shock what does this demonstrates
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5 0
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Calculate the volume of a gas at a pressure of 150 kpa if its volume at 180 kpa is 1500 L
Anastaziya [24]

Answer: 1800 L

Explanation:

Given that,

Original pressure of gas (P1) = 180 kPa

Original volume of gas (V1) = 1500 L

New pressure of gas (P2) = 150 kPa

New volume of gas (V2) = ?

Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

P1V1 = P1V2

180 kPa x 1500 L = 150 kPa x V2

270000 kPa•L = 150 kPa•V2

Divide both sides by 150 kPa

270000 kPa•L/150 kPa = 150 kPa•V2/150 kPa

1800L = V2

Thus, the new volume of the gas is 1800 liters.

8 0
3 years ago
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