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grandymaker [24]
2 years ago
13

A sample of hydrogen gas contains 4.8 x 1026 molecules of hydrogen. How many moles of hydrogen is this?

Chemistry
1 answer:
Travka [436]2 years ago
4 0

Answer:

797.34 moles of H₂

Explanation:

From the question given above, the following data were obtained:

Number of molecules of H₂ = 4.8×10²⁶ molecules

Number of mole of H₂ =?

From Avogadro's hypothesis,

1 mole of H₂ = 6.02×10²³ molecules

With the above information, we can determine the number of mole of H₂ that contains 4.8×10²⁶ molecules as follow:

6.02×10²³ molecules = 1 mole of H₂

Therefore,

4.8×10²⁶ molecules = 4.8×10²⁶ / 6.02×10²³

4.8×10²⁶ molecules = 797.34 moles

Thus, 797.34 moles of H₂ contains 4.8×10²⁶ molecules.

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Which is a characteristic of mixtures?
d1i1m1o1n [39]

Answer: They can be separated by physical processes.

Explanation: A mixture is made up of two or more substances that are not chemically combined and can be easily separated into its constituents by physical methods.

8 0
3 years ago
A 5.0 milliliter sample of a substance has a mass of 12.5 grams. What is the mass of a 100 milliliter sample of the same substan
exis [7]

Answer:

It sould be 250 grams

Explanation:

4 0
2 years ago
Identify the main purpose of the Periodic Table. *
saw5 [17]

The periodic table is one of the most important tools in the history of chemistry. It describes the atomic properties of every known chemical element in a concise format, including the atomic number, atomic mass and relationships between the elements. Elements with similar chemical properties are arranged in columns in the periodic table.

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Hope this answer helps you

4 0
3 years ago
An experimental spacecraft consumes a special fuel at a rate of 372 L/min. The density of the fuel is 0.730 g/mL and the standar
Karolina [17]

Explanation:

First, we will calculate fuel consumption is as follows.

         372 L/min \times 1000 ml/L \times 0.730 g/ml \times \frac{1}{60} min/s

           = 4526 g/s

Now, we will calculate the power as follows.

        Power = Fuel consumption rate × -enthalpy of combustion

                    = 4526 g/s \times -26.5 kJ/g

                    = 1.19 \times 10^{5} kW

Thus, we can conclude that maximum power (in units of kilowatts) that can be produced by this spacecraft is 1.19 \times 10^{5} kW.

5 0
3 years ago
What mass of CO was used up in the reaction with an excess of oxygen gas if 24.7g of carbon dioxide is formed? 2 CO + O2 > 2
Zolol [24]
Balance Chemical Equation,
                                      2 CO  +  O₂   →   2CO₂
Acc. to this reaction,
88 g (2 mole) of CO₂ was produced when  =  56 g (2 mole)of CO was reacted
So, 
24.7 g of CO₂ will be produced by reacting =  X g of CO

Solving for X,
                                    X  =  (56 g × 24.7 g) ÷ 88 g

                                    X  =  2.26 g ÷ 88 g

                                    X  =  0.0257 g of CO

Result:           
            0.0257 g of CO is required to be reacted with excess of O₂ to produce 24.7 g of CO₂.
7 0
2 years ago
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