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grandymaker [24]
3 years ago
13

A sample of hydrogen gas contains 4.8 x 1026 molecules of hydrogen. How many moles of hydrogen is this?

Chemistry
1 answer:
Travka [436]3 years ago
4 0

Answer:

797.34 moles of H₂

Explanation:

From the question given above, the following data were obtained:

Number of molecules of H₂ = 4.8×10²⁶ molecules

Number of mole of H₂ =?

From Avogadro's hypothesis,

1 mole of H₂ = 6.02×10²³ molecules

With the above information, we can determine the number of mole of H₂ that contains 4.8×10²⁶ molecules as follow:

6.02×10²³ molecules = 1 mole of H₂

Therefore,

4.8×10²⁶ molecules = 4.8×10²⁶ / 6.02×10²³

4.8×10²⁶ molecules = 797.34 moles

Thus, 797.34 moles of H₂ contains 4.8×10²⁶ molecules.

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The osmotic pressure of a saturated solution of strontium sulfate at 25 ∘C∘C is 21 torrtorr. Part A What is the solubility produ
USPshnik [31]

Answer

solubility product = 3.18x 10^-7

Explanation:

We were given the pressure in torr then we need to convert to atm for consistency, ten we have

21torr/760= 0.0276315789 atm

21 Torr = .0276315789 atm

P = i M S T

M = P / iRT

Where p is osmotic pressure

T= temperature= 25C+ 273= 298K

for XY vanthoff factor i = 2

S = 0.0821 L-atm / mol K

M = .0276315789 atm / (2)(0.0821 L atm / K mole)(298 K)

M = 0.000564698046 mol/liters

solubility= 0.000564698046 mol/liters

Ksp = [X+][Y-]

Ksp = X^2

Ksp = [Sr^+2] * [SO4^-2]

Ksp = X^2

Ksp = (0.000564698046)^2

Ksp = 3.18883883 × 10-7

Ksp = 3.18x 10^-7

solubility product = 3.18x 10^-7

Therefore, the solubility product of this salt at 25 ∘C∘C is 3.18x 10^-7

7 0
3 years ago
What would the volume of a gas be at 150c if had of volume of 693 ml at 45 c​
Vlad1618 [11]

Answer:

Explanation:

T1 = 150°C = (150 + 273.15)K = 423.15K

T2 = 45°C = (45 + 273.15)K = 318K

V1 = 693mL = 693cm³

Applying Charle's law, the volume of a given gas is directly proportional to is temperature provided that pressure remains constant.

V = kT

V1 / T1 = V2 / T2

693 / 423.15 = V2 / 318

V2 = (693 * 318) / 423.15 = 520.79cm³

The new volume of the gas is 520.79cm³

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3 years ago
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Answer: 3 & 4

Explanation:

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Write a balanced chemical equation for the neutralization reaction between phosphoric acid and rubidium hydroxide.
Anastaziya [24]
Phosphoric acid is a weak acid, while rubidium hydroxide is a strong acid.

H₃PO₄ + RbOH --> Rb₃PO₄ + H₂O

We get Rb₃PO₄ because PO₄ has a charge of 3-, that is PO₄³⁻. Rb has a charge of 1+. You give the subscript of one the charge of the other as this is an ionic compound. So you end up with Rb₃PO₄, a neutral compound.

Now let's balance the equation:
H₃PO₄ + 3RbOH --> Rb₃PO₄ + 3H₂O
5 0
3 years ago
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