The volume of 0.98 mol oxygen gas at 275 k and a pressure of 2.0 atm is 11.06L.
<h3>How to calculate volume?</h3>
The volume of a given mass of gas can be calculated using the following formula:
PV = nRT
Where;
- P = pressure
- V = volume
- R = gas law constant
- T = temperature
- n = number of moles
According to this question, 0.98 moles of oxygen gas at 275 k contains a pressure of 2.0 atm. The volume is calculated as follows:
2 × V = 0.98 × 0.0821 × 275
2V = 22.13
V = 11.06L
Therefore, the volume of 0.98 mol oxygen gas at 275 k and a pressure of 2.0 atm is 11.06L.
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Answer:
x² = mutiphy by them self
Explanation:
Answer:
The arm that was not sprayed with anything
Explanation:
The control group would be <u>the arm that was not sprayed with anything</u>.
<em>The control group during an experiment is a group that forms the baseline for comparison in other to determine the effects of a treatment. The control group does not include the variable that is being tested and as such, it provides the benchmark to measure the effects of the tested variable on the other group - the experimental group. In this case, the experimental group would be the arm that was sprayed with the repellent.</em>
When a substance is heated, it gains thermal energy. Therefore, its particles move faster and its temperature rises.
Answer : The value of 
for this reaction is 36.18 kJ
Explanation :
First law of thermodynamic : It states that the energy can not be created or destroyed, it can only change or transfer from one state to another state.
As per first law of thermodynamic,
where,
= internal energy of the system
q = heat added or rejected by the system
w = work done
As we are given that:
q = 38.65 kJ
w = -2.47 kJ (system work done on surrounding)
Now put all the given values in the above expression, we get:
Therefore, the value of for this reaction is 36.18 kJ
