Answer:
creamy with milk and chocolate
Answer:
Explanation:
Let 100 m/s be the velocity of projection.
So horizontal component
= 100 cos42
= 74.31 m /s
Vertical component = - 100 sin 42 . in upward direction
66.91 m/s
Net displacement = 2.1 downwards ( + ve )
Using s = ut + 1/2 gt²
2.1 = - 66.91 t + .5 x 9.8 x t²
4.9 t² - 66.91 t - 2.1 = 0
t = 13.685 s
Horizontal distance covered
= 13.685 x 74.31
= 1016.93 m
If angle of projction is 40°
So horizontal component
= 100 cos40
= 76.60 m /s
Vertical component = - 100 sin 42 . in upward direction
64.27 m/s
Net displacement = 2.1 downwards ( + ve )
Using s = ut + 1/2 gt²
2.1 = -76.60 t + .5 x 9.8 x t²
4.9 t² - 76.60 t - 2.1 = 0
t = 15.659 s
Horizontal distance covered
= 15.659 x 76.60
= 1199.49 m
So horizontal range is increased , if angle of projection is increased .
power = (voltage) x (current)
17 w = (5 v) x (current)
current = (17 w) / (5 v) = 3.4 Amperes
Answer:
Vertex: Point where the principal axis and mirror meet
Focal point: Point we are reflected light converges or appears to diverge
Focal length: distance from the center of a mirror to the focal point
Principal axis: line that runs to the center of curvature to a mirror
Center of curvature: sensor of spherical mirror from which a curved mirror was cut
Explanation:
Just did the assignment on Edge.
Answer:
As a body moving upward
T=real weight + apparent weight
T=550+490
T=1040
hope u will get the answer:)
Explanation:
