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KiRa [710]
3 years ago
14

When 560,000 is written in scientific notation, the power of 10 is

Physics
2 answers:
gayaneshka [121]3 years ago
8 0

Answer:

5.6 x 10^5

Explanation:

The scientific notation is the notation in which the decimal point is place after the first digit and then express in the exponents of 10.

So, 560000 = 5.6 x 10^5

Take one more example

0.00234 = 2.34 x 10^(-3)

attashe74 [19]3 years ago
4 0
The answer would be 5.6x10^5
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A simple, direct-current electrical circuit is shown below.
kap26 [50]

The direction of current flow is given by an arrow in the electrical circuit.

Several categories are used to categorise electrical circuits. One-way current only flows through a direct-current circuit. As with most residential circuits, an alternating-current circuit is a channel for transmitting electrical current that pulses back and forth numerous times each second.

A battery or generator, a device that provides energy to the charged particles that make up the current, a device that uses current, such as a lamp, an electric motor, or a computer, and the connecting wires or transmission lines make up an electrical circuit.

A source of electrical power, two wires that can transmit current, and a light bulb make up an electrical circuit. Both wires have one end connected to a cell terminal and the other end connected to a light bulb. When the light bulb is turned off, the electrical circuit is disrupted.

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5 0
2 years ago
A ship is towed through a narrow channel by applying forces to three ropes attached to its bow. Determine the magnitude and orie
Y_Kistochka [10]

This question is solved using an available similar problem as data provided for the forces was not given.

Repeat the same steps outlined for your problem.

Regards.

Answer:

F = 1.598 KN , Q = 90 degree (+ y-axis)

Explanation:

Sum of Forces in x-direction to the left (+)

2 cos (30) + 3cos (60) + F*cos (Q) = F_a   ..... 1

Sum of Forces in y-direction to the up (+)

2 sin (30) + F*sin (Q) - 3 sin (60)  ...... 2

Using Eq 2 and solve:

F*sin (Q) = 1.598 KN

F_min when sin (Q) is max, max possible value of sin(Q) = 1 @ Q = 90 degrees.

Hence,

F_min = 1.598 KN

Using Eq 1 @ Q = 90 degrees and F = 1.598 KN:

F_a = 2 cos (30) + 3cos (60)  = 3.2 KN

6 0
3 years ago
The unit for momentum is which of the following?
Alika [10]

(any unit of mass) x (any unit of speed)  is a unit of momentum.

The only choice on the list with the dimensions of (mass) x (speed)
is 'c'.

'a' is a unit of force.
'b' is meaningless.
'c' is a false statement.
6 0
3 years ago
As a pole of a 2nd-order discrete-time system moves away from the origin in the z-plane, while its phase remains constant, the d
Rudik [331]

Answer:

False

Explanation:

When the location of the poles changes in the z-plane, the natural or resonant frequency (ω₀) changes which in turn changes the damped frequency (ωd) of the system.

As the poles of a 2nd-order discrete-time system moves away from the origin then natural frequency (ω₀) increases, which in turn increases damped oscillation frequency (ωd) of the system.

ωd = ω₀√(1 - ζ)

Where ζ is called damping ratio.

For small value of ζ

ωd ≈ ω₀

4 0
3 years ago
A block, M1=10kg, slides down a smooth, curved incline of height 5m. It collides elastically with another block, M2=5kg, which i
erma4kov [3.2K]

Answer:

2.86 m

Explanation:

Given:

M₁ = 10 kg

M₂ = 5 kg

\mu_k = 0.5

height, h = 5 m

distance traveled, s = 2 m

spring constant, k = 250 N/m

now,

the initial velocity of the first block as it approaches the second block

u₁ = √(2 × g × h)

or

u₁ = √(2 × 9.8 × 5)

or

u₁ = 9.89 m/s

let the velocity of second ball be v₂

now from the conservation of momentum, we have

M₁ × u₁ = M₂ × v₂

on substituting the values, we get

10 × 9.89 = 5 × v₂

or

v₂ = 19.79 m/s

now,

let the velocity of mass 2 when it reaches the spring be v₃

from the work energy theorem,  we have

Work done by the friction force = change in kinetic energy of the mass 2

or

0.5\times5\times9.8\times2 = \frac{1}{2}\times5\times( v_3^2-19.79^2)

or

v₃ = 20.27 m/s

now, let the spring is compressed by the distance 'x'

therefore, from the conservation of energy

we have

Energy of the spring =  Kinetic energy of the mass 2

or

\frac{1}{2}kx^2=\frac{1}{2}mv_3^2

on substituting the values, we get

\frac{1}{2}\times250\times x^2=\frac{1}{2}\times5\times20.27^2

or

x = 2.86 m

8 0
3 years ago
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