Question

Odina walked down the hall at school from the cafeteria to

Answer 1

Answer:

Explanation:

As we know that when graph is plotted with the position and time then it shows that it will move with uniform speed

So here it is moving 2.6 m in 2 s

so speed is given as

$v = \frac{2.6}{2}$

$v = 1.3 m/s$

Part a)

when she reach 25 m from cafeteria

time taken by her

$t = \frac{d}{v}$

$t = \frac{25}{1.3}$

$t = 19.2 s$

Part b)

When she will reach 25 m from band room

then total distance moved from cafeteria is

$d = 100 - 25 = 75m$

time taken by her

$t = \frac{75}{1.3}$

$t = 57.7 s$

Part c)

Since Odina is moving at constant speed

so the position time graph must be a straight line graph

Answer 2

I think no 1 not sure