Answer:circulatory system
The work done by the applied force = 650 J
Given the mass of the box = 40 kg
The displacement of the box on applying force = 5 m
Applied horizontal force = 130 N
The co-efficient of friction between box and floor is = 0.3
We have to find the work done by the applied force.
Work done by the applied force = Applied Force x Displacement of the box
= 130 N x 5 m
= 650 J
[Here the unit Nm is known as Joule(J) ]
We have the co-efficient of friction. So,
The force applied due to friction = Mass of the box x Co-efficient of friction x Acceleration due to gravity
= 40 kg x 0.3 x 9.8
= 117.6 N
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Answer: C
Gravitational Force
Weak Nuclear Force
Electromagnetic Force
Strong Nuclear Force
Explanation: i did the quiz on, a p e x
Answer: the average density (in kg/m3) of the log is 400 kg/m³
Explanation:
Given that;
a log with uniform-diameter floats with 60.0% of its length above water.
from the Archimedes principle formula;
friction submerged = Average density of object / density of fluid. --- equ 1
We know that; density of water = 1000 kg/m³
now the log floats with 60.0% of its length above water
so submerged fraction is 100% - 60% = 40% = 0.40
from our equation;
friction submerged = Average density of object / density of fluid
we substitute
0.40 = Average density of object / 1000 kg/m³
Average density of object = 0.40 × 1000
Average density of object = 400 kg/m³
Therefore; the average density (in kg/m3) of the log is 400 kg/m³
We need to the where the arrows are..
