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Crank
3 years ago
14

A polar bear runs at a speed of 8.3 m/s, how far will it travel in 60 seconds?

Physics
2 answers:
Kay [80]3 years ago
6 0
498 mps since you just times 8.3 by 60
Elanso [62]3 years ago
3 0

Answer:

it would have run 498 miles

Explanation:

if the polar bear runs 8.3 every second then multiply 8.3 times sixty to get 498

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The brachialis attaches to the forearm .035 m from the elbow at an angle of 32 deg. If the brachialis produces 750 N of force, w
jek_recluse [69]

Answer:

XY=636N

Explanation:

From the question we are told that:

Distance d=0.35m

Angle \theta=32\textdegree

Force F=750N

Generally the equation for magnitude of the stabilizing component of the brachialis force is mathematically given by

 XY=Fcos\theta

 XY=750cos 32\textdegree

 XY=636N

4 0
3 years ago
On a Saturday afternoon, you decide to pay a neighborhood kid to mow your lawn. The kid usesa manual push lawn mower with a mass
Mars2501 [29]

Answer with Explanation:

We are given that

A.Mass,m=12 kg

\theta=53^{\circ}

\mu_k=0.16

Speed,v=1.5m/s

Net force in x direction must be zero

F_{net}=0

Fsin\theta-f=0

Fsin\theta=f

Net force in y direction

N-mg-Fcos\theta=0

N=mg+Fcos\theta

f=\mu_kN=\mu_k(mg+Fcos\theta)

Fsin\theta=\mu_k(mg+Fcos\theta)

Fsin\theta=\mu_kmg+\mu_kFcos\theta

Fsin\theta-\mu_kFcos\theta=\mu_kmg

F(sin\theta-\mu_kcos\theta)=\mu_kmg

F=\frac{\mu_kmg}{sin\theta-\mu_kcos\theta}

Power,P=Fv

P=\frac{\mu_kmg}{sin\theta-\mu_kcos\theta}v

Where g=9.8m/s^2

B.Substitute the values

P=\frac{0.16\times 12\times 9.8}{sin53-0.16cos53}\times 1.5

P=40.17W

6 0
3 years ago
a mass of 10kg is placed on a horizontal table with coefficient of friction is 0.5. if the mass is static, determine weight of t
zloy xaker [14]

Answer:

10

Explanation:

5 0
3 years ago
Why might surface mining be less risky for miners than underground mining?
aev [14]
Surface miners work aboveground. (Apex) ^-^

6 0
2 years ago
Read 2 more answers
A particle R moves with a velocity of 6 m/s due East and another particle S moves at 8 m/s due South. What is the magnitude of t
cluponka [151]

Answer:

10

Explanation:

We can look at this problem as a triangle, r is the hypotenuse so if we take the square root of 6^2+8^2 we get 10

6 0
2 years ago
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