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KIM [24]
3 years ago
7

A white billiard ball with mass mw = 1.43 kg is moving directly to the right with a speed of v = 3.39 m/s and collides elastical

ly with a black billiard ball with the same mass mb = 1.43 kg that is initially at rest. The two collide elastically and the white ball ends up moving at an angle above the horizontal of θw = 38° and the black ball ends up moving at an angle below the horizontal of θb = 52°. 1)What is the final speed of the white ball? m/s 2)What is the final speed of the black ball? m/s 3)What is the magnitude of the final total momentum of the system? kg-m/s 4)What is the final total energy of the system?

Physics
1 answer:
Anna71 [15]3 years ago
4 0

Answer: a) VW = 1.28m/s

b) Vb = 3.86m/s

c) p = 5.82kgm/s

d) E = 11.84J

Explanation: To solve this question, we make use of explosion formula in linear momentum concept.

Please find the attached file for the solution

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An ostrich lays the largest bird egg. A typical diameter for an ostrich egg at its widest part (diameter) is 12 cm (0.12 m). Sup
Vanyuwa [196]

The centripetal acceleration is the ratio of the tangential speed and the

radius of the shell.

The tangential speed of the part of the shell is approximately <u>0.12961 m/s</u>

Reasons;

The widest diameter of the egg, d = 12 cm = 0.12 m

The given centripetal acceleration, a_c = 0.28 m/s²

Required:

The tangential speed of the bird.

Solution;

\displaystyle Centripetal \ acceleration, \ a_c = \mathbf{\frac{v^2}{r}}

Where;

\displaystyle r = The \ radius \ of \ the \ egg \ shell = \frac{d}{2}

v = The tangential speed

Which gives;

\displaystyle r = \frac{0.12}{2} = 0.06

\displaystyle 0.28 \, m/s^2 = \frac{v^2}{0.06 \, m}

v² = 0.28 m/s² × 0.06 m = 0.0168 m²/s²

v = √(0.0168 m²/s²) ≈ 0.12961 m/s

The tangential speed, v = <u>0.12961 m/s</u>

<u />

Learn more about centripetal acceleration here:

brainly.com/question/79801

8 0
3 years ago
Please help, I need help with this test question
Arturiano [62]

I believe this is right-

for the first question, it should be fluffy

and for the second it should be spot

potential energy is unused

kinetic energy is being used

4 0
3 years ago
Give an example of a situation when it would be appropriate to round a number and a situation in which it would not be appropria
Ivan

it would be appropriate to round a number when you are talking about people or animals. Ex. it fits 10 1/2 people. it will most likely fit 9-11 people.

You it is not appropriate to round with money.

Ex. If you owe someone $9.43 you don't just give them $9


6 0
3 years ago
Johnny walked to the other side of his building using the following steps: 10 meters North, 20 meters to the West, 40 meters Sou
nataly862011 [7]

<u>Answer: </u>

  Distance traveled = 70 meters

  Displacement = 36.06 meters

<u>Explanation: </u>

 Let north be positive Y and east be positive X

 10 meters north, displacement = 10 j meters

 20 meters west, displacement = -20 i meters

 40 meters south, displacement = -40 j meters

 Total displacement = (10 j - 20 i – 40 j) meters = (- 20 i - 30 j) meters

 Magnitude of displacement = \sqrt{20^2+30^2}=\sqrt{1300}= 36.06 meters

 Distance traveled = 10+20+40 = 70 meters

6 0
3 years ago
One end of a metal rod is in contact with a thermal reservoir at 745. K, and the other end is in contact with a thermal reservoi
Masteriza [31]

Answer:

a)S_1=-9.65}\ J/K

b)S_2=71.18\ J/K

c) 0 J/K

d)S= 61.53 J/K

Explanation:

Given that

T₁ = 745 K

T₂ = 101 K

Q= 7190 J

a)

The entropy change of reservoir 745 K

S_1=-\dfrac{7190}{745}\ J/K

Negative sign because heat is leaving.

S_1=-9.65}\ J/K

b)

The entropy change of reservoir 101 K

S_2=\dfrac{7190}{101}\ J/K

S_2=71.18\ J/K

c)

The entropy change of the rod will be zero.

d)

The entropy change of the system

S= S₁ + S₂

S = 71.18 - 9.65 J/K

S= 61.53 J/K

3 0
4 years ago
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