Given:
Area of the largest square = 67 units²
To find:
The area of the smallest squares.
Solution:
Area of square = s²
s² = 67
Here hypotenuse of the right triangle = Side of the largest square
Using Pythagoras theorem,
In right triangle, square of the hypotenuse is equal to the sum of the squares of the other two sides.
<u>Checking possible answers:</u>
Option A: 8 and 58
Using Pythagoras theorem,
8 + 58 = 66
This is not equal to 67.
It is not true.
Option B: 7 and 60.
Using Pythagoras theorem,
7 + 60 = 67
This is equal to 67 (hypotenuse)
It is true.
Option C: 11 and 56
Using Pythagoras theorem,
11 + 56 = 67
This is equal to 67 (hypotenuse)
It is true.
Therefore 7, 60 and 11, 56 could be the areas of the smaller squares.