1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BabaBlast [244]
3 years ago
5

The owner of the West End Kwick Fill Gas Station wishes to determine the proportion of customers who pay at the pump using a cre

dit card or debit card. He surveys 100 customers and finds that 80 paid at the pump. (Round your answers to 2 decimal places.) Estimate the value of the population proportion.
Mathematics
1 answer:
GalinKa [24]3 years ago
3 0

Answer: 0.80

Step-by-step explanation:

Given : The owner of the West End Kwick Fill Gas Station wishes to determine the proportion of customers who pay at the pump using a credit card or debit card.

He surveys 100 customers and finds that 80 paid at the pump.

Then, sample proportion= \dfrac{80}{100}=0.80

Since , the best point estimate for population proportion is sample proportion.

Therefore, the estimated value for population proportion =0.80

You might be interested in
Based on the model ​N(1154​,81​) describing steer​ weights, what are the cutoff values for
skad [1K]
Can’t see the model.......................
7 0
3 years ago
PIC IS THE QUESTION AND ANSWERS
Yanka [14]
4/5 and 40/50 are both equivalent
4 0
3 years ago
Read 2 more answers
Shaded area=40<br> Find x <br> Width=3x<br> Length=4x<br> Not shaded area=2x
Mashutka [201]
In the process of laying out the question, you have given us important facts about the shaded area and the unshaded area. Now step back for just a second. If they're that deeply involved in the question, do you honestly expect that anybody can answer the question without seeing the picture of them ? ! ?
6 0
3 years ago
Please help i will give you brainliest and every yhing
Lina20 [59]

first subtract the last equation from the first. this gives:-

-x + y = -8 .....................(1)

Then multiply the first equation by 2 and add it to the 2nd equations This gives

9x = 18  

so x = 2

and from equation  (1)  y = -8 + 2 = -6

Substituting for x and y in the second equation

z =  (24 -5(2) -12) / 2 =   1


Answer is choice b.

7 0
3 years ago
Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
Other questions:
  • (-3y^2 — 5у — 2) +(-7y^2- 5y + 2)
    13·2 answers
  • Can someone help with this question
    11·2 answers
  • 1. Use successive differences to classify the function represented in the table. Here is the table:
    10·1 answer
  • What does it mean for a product of factors to be expressed using exponents
    15·1 answer
  • Why won't a tripod tip over
    15·2 answers
  • 7000(1+.065/12)12*15
    14·1 answer
  • A school paid $31.25 for each calculator. If the school spent $500 on calculators, how many did the school buy?
    7·2 answers
  • Ryan's unpaid credit card balance was $1853.68. His APR is 24.9%. What is his new balance after he makes one new transaction for
    8·1 answer
  • What is the quotient of 1,456 and 7?
    13·2 answers
  • What's the domain and range?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!