Answer:
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Answer:
The neutron loses all of its kinetic energy to nucleus.
Explanation:
Given:
Mass of neutron is 'm' and mass of nucleus is 'm'.
The type of collision is elastic collision.
In elastic collision, there is no loss in kinetic energy of the system. So, total kinetic energy is conserved. Also, the total momentum of the system is conserved.
Here, the nucleus is still. So, its initial kinetic energy is 0. So, the total initial kinetic energy will be equal to kinetic energy of the neutron only.
Now, final kinetic energy of the system will be equal to the initial kinetic energy.
Now, as the nucleus was at rest initially, so the final kinetic energy of the nucleus will be equal to the initial kinetic energy of the neutron.
Thus, all the kinetic energy of the neutron will be transferred to the nucleus and the neutron will come to rest after collision.
Therefore, the neutron loses all of its kinetic energy to nucleus.
Answer:
a) 24.43 radians per second
b) 268.73 inches per second
Explanation:
a) The angular speed of the fan on Celsius degrees/second is 1400, so we should convert that value to radians using the fact that 2π rad = 360 °C:


b) Linear speed on a point of the blade is related with angular speed of the fan by the equation

with v linear speed, ω angular speed and r the radius of the blades. So:

Radians isn't really a unity; it is dimensionless so we can put it or not. So:

The force acting on a moving charge is known as the magnetic force. The force acting on the charge will be 3.75 N.
<h3>What is the force exerted on the charge?</h3>
Magnetic fields only exert a force on a moving electric charge. A moving charge generates a magnetic field. With an increase in charge and magnetic field strength, this force rises.
when charges have higher velocities, the force is stronger. However, the magnetic force is always perpendicular to the velocity.
Mathematically the force exerted on the charge will be
F=qvBsinα
F= force acting on the charge
v = velocity of charge
q = charge
F=qvBsinα
F=2.5×10⁻⁶×5.0×10³×3.0×10²
F=37.5 N
Hence The force acting on the charge will be 3.75 N.
To learn more about the force acting on charge refer to ;
brainly.com/question/451411
F = q V B sinα
Where F is the force applied to a moving charge.
V = charge velocity
q stands for charge.
α = angle between V and B directions
As a result, the moving charge is subjected to a force of 3.75 Newton.
Answer:
solution:
dT/dx =T2-T1/L
&
q_x = -k*(dT/dx)
<u>Case (1) </u>
dT/dx= (-20-50)/0.35==> -280 K/m
q_x =-50*(-280)*10^3==>14 kW
Case (2)
dT/dx= (-10+30)/0.35==> 80 K/m
q_x =-50*(80)*10^3==>-4 kW
Case (2)
dT/dx= (-10+30)/0.35==> 80 K/m
q_x =-50*(80)*10^3==>-4 kW
Case (3)
q_x =-50*(160)*10^3==>-8 kW
T2=T1+dT/dx*L=70+160*0.25==> 110° C
Case (4)
q_x =-50*(-80)*10^3==>4 kW
T1=T2-dT/dx*L=40+80*0.25==> 60° C
Case (5)
q_x =-50*(200)*10^3==>-10 kW
T1=T2-dT/dx*L=30-200*0.25==> -20° C
note:
all graph are attached