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Pachacha [2.7K]
3 years ago
5

Does anyone know 3-6?

Physics
2 answers:
Andrei [34K]3 years ago
6 0
3). b
4). c
5). d
6). d
Julli [10]3 years ago
5 0
-3, because you have to subtract 
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At standard temperature and pressure, carbon dioxide has a density of 1.98 kg/m3. What volume does 1.70 kg of carbon dioxide occ
nikitadnepr [17]

Answer:

<h2>volume= 0.85m^3</h2>

Explanation:

<em>The density of a substance is defined as the mass per unit volume of the substance, the unit is in kg/m^3 and it is represented by the greek letter rho</em>

Step one:

given data

we are told that the density  of Co2=  1.98 kg/m3

and the mass of Co2 is= 1.70 kg

we know the relation between mass, volume and density is

density=mass/volume

make volume subject of formula we have

volume=mass/density

substitute we have

volume=1.7/1.98\\\\volume= 0.85m^3

8 0
3 years ago
an object is thrown with an initial horizontal velocity of 10 meters per second and take approximately 9 seconds to reach the gr
pantera1 [17]

The horizontal velocity was constant, so:

s = vt

s = 10\cdot9

s = 90

it traveled 90meters

6 0
3 years ago
How is velocity ratio of wheel and axle calculatedaad<br>​
iogann1982 [59]

Answer:

VR = \frac{Radius of wheel}{Radius of axle}

Explanation:

A machine is a device that can be used to overcome a load by the application of an effort through a pivot. Examples are: pulleys, wedge, screw jack, wheel and axle etc.

The wheel and axle is a simple device that can be used to lift a load through a height. Its velocity ratio (VR) can be determined by:

VR = \frac{Radius of wheel}{Radius of axle}

Note that for a practical wheel and axle, the radius of the wheel is greater than the radius of the axle.

3 0
3 years ago
1.- La gráfica muestra la variación de la aceleración a de un objeto con el tiempo t.
STatiana [176]

Answer:

Te ayudo con una de prueba $

Explanation:

5 0
3 years ago
In the middle of a thunderstorm, a lightning bolt flashes. It takes Roberto 5 seconds to
Gemiola [76]

Answer:

 v = 344.1 m / s    

 d = 1720.5 m

Explanation:

For this problem we must calculate the speed of sound in air at 22ºC

           v = 331 RA (1+ T / 273)

we calculate

           v = 331 RA (1 + 22/273)

           v = 344.1 m / s

the speed of the wave is constant,

           v = d / t

           d = v t

we calculate

           d = 344.1   5

           d = 1720.5 m

5 0
2 years ago
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